Answer:
[NaCl] = 1.72 M
Explanation:
First of all, we balance the equation:
BaCl₂ + Na₂SO₄ → 2NaCl + BaSO₄
We convert mass of barium chloride to moles
45 g . 1mol / 208.23g = 0.216 moles
Ratio is 1:2. This means, that our moles of reactant may produce the double of moles, of product.
0.216 . 2 = 0.432 moles of NaCl are been produced.
Molarity is mol/L. We convert volume of water from mL to L
250 mL . 1L /1000 mL = 0.250 L
[NaCl] = 0.432 mol/0.250L = 1.72 M
