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4 years ago

11

Which type of white blood cell produces antibodies that help the body fight infection?

1 answer:

Assoli18 [71]4 years ago

5 0

B lymphocytes
Lymphocytes are one of the main types of immune cells. Lymphocytes are divided mainly into B and T cells. B lymphocytes produce antibodies - proteins (gamma globulins) that recognize foreign substances (antigen) and attach themselves to them. B lymphocytes (or B cells) are each programmed to make one specific antibody.

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Given that the density of iron is 7.9 g/cm3, what would be the volume of a 15.8 g piece of iron

Anuta_ua [19.1K]

Answer:

2cm^3

Explanation:

Use the density triangle: D=MxV

Switch for variables, V=M/D

Plug in numbers, 15.8g/7.9g/cm^3=2cm^3

7 0

4 years ago

A substance that is ______ will NOT dissolve in a solvent. A) freezing B) insoluble C) evaporating D) soluble

Alexxandr [17]

Answer:

insoluble

Explanation:

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3 years ago

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If a tractor trailer and a car are both traveling 50km/h when they hit which will have the greatest change in speed and directio

den301095 [7]

The tractor trailer will push the car when they hit so therefore the car will have to greatest change

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3 years ago

From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp

Nina [5.8K]

<u>Answer:</u> The concentration of $NH_3$ required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of $NiC_2O_4$ , we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of $NiC_2O_4$ = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M$

For the given chemical equations:

$NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}$

$Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9$

Net equation: $NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?$

To calculate the equilibrium constant, K for above equation, we get:

$K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48$

The expression for equilibrium constant of above equation is:

$K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}$

As, $NiC_2O_4$ is a solid, so its activity is taken as 1 and so for $C_2O_4^{2-}$

We are given:

$[[Ni(NH_3)_6]^{2+}]=0.016M$

Putting values in above equations, we get:

$0.48=\frac{0.016}{[NH_3]^6}}$

$[NH_3]=0.285M$

Hence, the concentration of $NH_3$ required will be 0.285 M.

7 0

3 years ago

A removal of the predator populations from an ecosystem would most likely result in

7nadin3 [17]

Answer:

The increase of prey

Explanation:

Without predators in the ecosysten prey population would increase

8 0

3 years ago

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