Answer:
a. 1100 meters.
b. Between B and C
c.1. Between point D and E
c2. Between point D and E
d. 3.7 m/s.
Explanation:
The girl travels the distance of 1100 meters from starting to the end. There is no motion occurs between B and C due to no change of distance value from 200 meters. Between point D and E, the girls covers 500 meters long distance and also covers fastest distance between point D and E because between point D and E, the girl covers 500 meters distance in 30 seconds which is the highest of all. The average speed of the girls is 3.7 meter/seconds if we divide total distance i.e. 1100 meters by time which is 300 seconds.
In order to be considered a vector, a quantity must include Magnitude (A) and Direction (D).
The cheetah can run 28,25 km
The components of the net force on the cart is determined as 67.66 N.
<h3>
Component of net force on the cart</h3>
The component of net force on the cart is determined by resolving the forces into x and y -components.
T1 = 30 N
T2 = 40 N
T1x = -30cos(0) = 30 N
T1y = 30sin(0) = 0
T2x = 40 x cos(30) = 34.64 N
T2y = 40 x sin(3) = 20 N
∑X = 30 N + 34.64 N = 64.64 N
∑Y = 0 + 20 N = 20 N
<h3>Resultant force</h3>
R = √(64.64² + 20²)
R = 67.66 N
Learn more about net force here: brainly.com/question/25239010
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Answer:
P₁ = 2.3506 10⁵ Pa
Explanation:
For this exercise we use Bernoulli's equation and continuity, where point 1 is in the hose and point 2 in the nozzle
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
A₁ v₁ = A₂ v₂
Let's look for the areas
r₁ = d₁ / 2 = 2.25 / 2 = 1,125 cm
r₂ = d₂ / 2 = 0.2 / 2 = 0.100 cm
A₁ = π r₁²
A₁ = π 1.125²
A₁ = 3,976 cm²
A₂ = π r₂²
A₂ = π 0.1²
A₂ = 0.0452 cm²
Now with the continuity equation we can look for the speed of water inside the hose
v₁ = v₂ A₂ / A₁
v₁ = 11.2 0.0452 / 3.976
v₁ = 0.1273 m / s
Now we can use Bernoulli's equation, pa pressure at the nozzle is the air pressure (P₂ = Patm) the hose must be on the floor so the height is zero (y₁ = 0)
P₁ + ½ ρ v₁² = Patm + ½ ρ v₂² + ρ g y₂
P₁ = Patm + ½ ρ (v₂² - v₁²) + ρ g y₂
Let's calculate
P₁ = 1.013 10⁵ + ½ 1000 (11.2² - 0.1273²) + 1000 9.8 7.25
P₁ = 1.013 10⁵ + 6.271 10⁴ + 7.105 10⁴
P₁ = 2.3506 10⁵ Pa