A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.314 kg of water?

Chemistry

1 answer:

Mariulka [41]3 years ago

5 0

Answer:

g NaCl = 424.623 g

Explanation:

<em>C</em> NaCl = 3.140 m = 3.140 mol NaCl / Kg solvent

∴ solvent: H2O

∴ mass H2O = 2.314 Kg

mol NaCl:

⇒ mol NaCl = (3.140 mol NaCl/Kg H2O)×(2.314 Kg H2O) = 7.266 mol NaCl

∴ mm NaCl = 58.44 g/mol

⇒ g NaCl = (7.266 mol NaCl)×(58.44 g/mol) = 424.623 g NaCl

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Photochemical chlorination of 1,2-dibromoethane gives a mixture of two stereoisomers of C2H3Br2Cl. Write their structural formul

Sever21 [200]

Answer:

Enantiomers

Chiral

Yes they will be formed in equal amount.

Explanation:

The Two possible stereo isomers are formed due to generation a chiral center in the molecule.

There will be a carbon with all the four groups different.

The two isomers will be called as enantiomers, which are non super-imposable mirror image of each other.

They are named as "R" or "S'" based on the selection rule.

The IUPAC names are also given in the figure.

The two isomers will be formed in equal amount as during photochemical chloriantion of a compound free radicals are generated (which are trigonal planar) and the other radical may attack from either side (front side or back side) giving the two stereo-isomers.