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Arada [10]
3 years ago
7

If the first stage provides a thrust of 5.31 ​mega-newtons [MN] and the space shuttle has a mass of 5,760,000 ​pound-mass ​[lbm​

], what is the acceleration of the spacecraft in miles per hour squared ​[mi/h2​]?
Physics
1 answer:
zysi [14]3 years ago
5 0

Answer:

The acceleration of the spacecraft is 16,367.62 miles/hr²

Explanation:

Given;

thrust of the spacecraft, F = 5.31 x 10⁶ N

mass of the spacecraft, m = 5,760,000 lbm = 2612692.051 kg

The acceleration of the spacecraft in m/s² is given by Newton's second law of motion;

F = ma

a = F / m

a = \frac{5.31*10^6 \ N}{2612692.051 \ kg}\\\\a = 2.0324 \ m/s^2

The acceleration in miles per hour square is given by;

a =2.0324 \frac{m}{s^2} *\frac{0.0006214 \ mile}{m}*(\frac{3600 \ s}{1 \ hour})^2\\\\  a =2.0324 \frac{m}{s^2} *\frac{0.0006214 \ mile}{m}*\frac{12960000 \ s^2}{1 \ hour^2}\\\\a = 16,367.62 \ miles/hr^2

Therefore, the acceleration of the spacecraft is 16,367.62 miles/hr²

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A leaf floating down from a tree is an example of an object in free fall.
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Answer:

Oi, mate its false

Explanation:

because if an leaf floats down from a tree it is not considered an object for a free-fall

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It took a student 30 minutes to drive from his home to campus on
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6. Mr. Leppold jumps out of a plane with a parachute...before the chute opens,
polet [3.4K]

1) He has both potential and kinetic energy

2) Before the parachute opens, the potential energy decreases and the kinetic energy increases

Explanation:

1)

The gravitational potential energy of a body is the energy possessed by the object due to its position in a gravitational field, and it is given by:

PE=mgh

where

m is the mass of the body

g is the acceleration of gravity

h is the height of the body above the ground

On the other hand, the kinetic energy of a body is the energy possessed by the body due to its motion; it is given by

KE=\frac{1}{2}mv^2

where

v is the speed of the object

Here Mr. Leppold has both potential and kinetic energy before opening the parachute, because:

- It is moving at a certain speed, so v\neq 0, therefore he has kinetic energy

- He is at a certain height above the ground, h\neq 0, therefore he has potential energy

2)

The total mechanical energy of Mr.Leppold is the sum of the potential and the kinetic energy:

E=PE+KE

According to the law of conservation of energy, in absence of air resistance, this quantity remains constant.

During the fall, the height of Leppold decreases: this means that as h decreases, the potential energy decreases  too.

However, the total energy E must remain constant: therefore, this means that the kinetic energy KE must increase, and this occurs because the speed of Mr. Leppold increases as he falls.

Learn more about kinetic and potential energy:

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8 0
3 years ago
At a distance r from a charge e on a particle of mass m the electric field value is
mel-nik [20]

At a distance r from a charge e on a particle of mass m the electric field value is  8.9876 × 10⁹ N·m²/C². Divide the magnitude of the charge by the square of the distance of the charge from the point. Multiply the value from step 1 with Coulomb's constant.

<h3>what is magnitude ?</h3>

Magnitude can be defined as the maximum extent of size and the direction of an object.

It is used as a common factor in vector and scalar quantities, as we know scalar quantities are those quantities that have magnitude only and vector quantities are those quantities have both magnitude and direction.

There are different ways where magnitude is used Magnitude of earthquake,  charge on an electron, force, displacement, Magnitude of gravitational force

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7 0
1 year ago
A plastic rod that has been charged to − 15 nC touches a metal sphere. Afterward, the rod's charge is − 5.0 nC.
Natali5045456 [20]

Answer:

B) electrons transferred from sphere to rod.

(2) 1.248 x 10¹¹ electrons were transferred

Explanation:

Given;

initial charge on the plastic rod, q₁ = 15nC

final charge on the plastic rod, q₂ = - 5nC

let the charge acquired by the plastic rod = q

q + 15nC = -5nC

q = -5nC - 15nC

q = -20 nC

Thus, the plastic rod acquired excess negative charge from the metal sphere.

Hence, electrons transferred from sphere to rod

B) electrons transferred from sphere to rod.

2) How many charged particles were transferred?

1.602 x 10⁻¹⁹ C = 1 electron

20 x 10⁻⁹ C = ?

= 1.248 x 10¹¹ electrons

Thus,1.248 x 10¹¹ electrons were transferred

7 0
3 years ago
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