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4 years ago

An approaching storm is moving at 15 km an hour what do you need to know to determine its velocity

Physics

1 answer:

leva [86]4 years ago

5 0

Probable how long they were moving

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A football player threw a ball upward at an angle or 24 degrees with the horizontal with A velocity of 18 m/s. What are the vert

svet-max [94.6K]

Answer:

$V_y = 16.44\ m/s$

$V_y = 7.32\ m/s$

Explanation:

Given

$\theta = 24$

$Velocity\ (V) = 18m/s$

Required

Determine the vertical and horizontal components

The vertical (Vy) and horizontal (Vx) components is calculated as thus:

$V_x = Vcos\theta$

$V_y = Vsin\theta$

Calculating Vertical Components:

$V_y = Vsin\theta$

$V_y = 18 * sin24$

$V_y = 18 * 0.40673664307$

$V_y = 7.32125957526$

$V_y = 7.32\ m/s$ --- Approximated

Calculating Horizontal Components:

$V_x = Vcos\theta$

$V_x = 18 * cos24$

$V_x = 18 * 0.91354545764$

$V_x = 16.4438182375$

$V_x = 16.44\ m/s$ --- Approximated

4 0

3 years ago

Of the four states of matter, which has particles that are the most tightly packed together?

iren2701 [21]

Depending on what you are working with, it would be a solid

4 0

3 years ago

A tool that uses lenses to focus light and create useful images

lianna [129]

the answer your looking for is Optical instrument.

5 0

3 years ago

Read 2 more answers

Determine the gravitational potential energy, in kJ, of 3 m3 of liquid water at an elevation of 40 m above the surface of Earth.

melomori [17]

Explanation:

We will calculate the gravitational potential energy as follows.

$P.E_{1} = mgz_{1}$

$P.E_{1} = (\rho V)gz_{1}$

= $1000 kg/m^{3} \times 3 m^{3} \times 9.7 \times 40 m$

= 1164000 J

or, = 1164 kJ (as 1 kJ = 1000 J)

Now, we will calculate the change in potential energy as follows.

$\Delta P.E = mg(z_{2} - z_{1})$

= $\rho \times V \times g (z_{2} - z_{1})$

= $1000 \times 3 \times 9.7 (10 - 40)m$

= -873000 J

or, = -873 kJ

Thus, we can conclude that change in gravitational potential energy is -873 kJ.

4 0

3 years ago

A rocket in deep space has an empty mass of 220 kg and exhausts the hot gases of burned fuel at 2500 m/s. What mass of fuel is n

Scilla [17]

Answer:

Explanation:

Let fuel is released at the rate of dm / dt where m is mass of the fuel

thrust created on rocket

= d ( mv ) / dt

= v dm / dt

this is equal to force created on the rocket

= 220 dv / dt

so applying newton's law

v dm / dt = 220 dv / dt

v dm = 220 dv

dv / v = dm / 220

integrating on both sides

∫ dv / v = ∫ dm / 220

lnv = ( m₂ - m₁ ) / 220

ln4000 - ln 2500 = ( m₂ - m₁ ) / 220

( m₂ - m₁ ) = 220 x ( ln4000 - ln 2500 )

( m₂ - m₁ ) = 220 x ( 8.29 - 7.82 )

= 103.4 kg .

8 0

4 years ago