Answer:
a) 1725.93 rpm
b) α = 3.012 rad/s²
Explanation:
The centrifugal acceleration is given by
a = v²/r
a = 1000 g = 1000 × 9.8 = 9800 m/s²
v = velocity = ?
r = radius of motion = 300 mm = 0.3 m
9800 = v²/0.3
v² = 2940
v = 54.22 m/s
v = rw
w = angular speed
54.22 = 0.3 × w
w = 54.22/0.3 = 180.74 rad/s
w = 2πf
f = frequency in rev/s
180.74 = 2πf
f = 28.77 rev/s
f = 1725.93 rpm
b) Using the equations of motion,
Since the centrifuge starts from rest,
w₀ = 0 rad/s
w = 180.74 rad/s (equivalent to the f = 1725.93 rpm)
t = 1 min = 60 s
α = ?
w = w₀ + αt
180.74 = 0 + 60α
α = 3.012 rad/s²
Answer:
V=1601gal
Explanation:
Hello! This problem is solved as follows,
First we must raise the equation that defines the pressure at the bottom of the tank with the purpose of finding the height that olive oil reaches.
This is given as the sum due to the atmospheric pressure (1atm = 101.325kPa), and the pressure due to the weight of the olive oil, taking into account the above, the following equation is inferred.
P=Poil+Patm
P=total pressure or absolute pressure=26psi=179213.28Pa
Patm= the atmospheric pressure =101325Pa
Poil=pressure due to the weight of olive oil=0.86αgh
α=density of water=1000kg/m^3
g=gravity=9.81m/s^2
h= height that olive oil reaches
solving
P=Poil+Patm
P=Patm+0.86αgh
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Now we can use the equation that defines the volume of a cylinder.
V=
D=3ft=0.9144m
h=9.23m
solving
finally we use conversion factors to find the volume in gallons
Answer: I will ask my dad he knows
Explanation:
Answer:
222222222222222222Explanation:
Answer:
Hello your question is incomplete below is the complete question
Electronic components are often mounted with good heat conduction paths to a finned aluminum base plate, which is exposed to a stream of cooling air from a fan. The sum of the mass times specific heat products for a base plate and components is 5000 J/K, and the effective heat transfer coefficient times surface area product is 10 W/K. The initial temperature of the plate and the cooling air temperature are 295 K when 300 W of power are switched on. 1) Find the plate temperature after 10 minutes.
answer ; 311.36 k
Explanation:
Given data :
sum of mass * specific heat products for a base plate and components ( Mcp )
= 5000 J/K
effective heat transfer coefficient * surface area ( hA ) = 10 W/K
Initial temperature of plate and cooling air temperature( Tc ) = 295 k
power ( Q = W ) = 300 W
a) Determine plate temperature after 10 minutes
10 mins = 600 secs ( t )
heat supplied = change in temp + heat loss
Q * t = mCp ( ΔT ) + hA ( ΔT ) t
300*600 = 5000 * ( T -295 ) + 10 ( T -295 ) * 600
therefore ; T - 295 = 16.363
T = 311.36 K