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Alekssandra [29.7K]
4 years ago
7

The mass of the Sun is 2 × 1030 kg, and the mass of Saturn is 5.68 × 1026 kg. The distance between Saturn and the Sun is 9.58 AU

. Veronica is solving the following equation to calculate the orbital period of Saturn, but there is an error in the equation. T = What should Veronica change to correct the equation? change the position of 2 x 1030 kg and 9.58 AU change 2 x 1030 kg to 5.68 x 1026 kg change the square root to a cube root change 9.58 AU to the distance in meters
Physics
2 answers:
GREYUIT [131]4 years ago
5 0
Not the answer but the answer will nit be  B. hope yall find the answer
USPshnik [31]4 years ago
5 0

The correct answer is D.

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A stone was dropped off a cliff and hit the ground with a speed of 96 ft/s. What is the height of the cliff? (Use 32 ft/s2 for t
nadezda [96]
The initial velocity of the stone is 0 ft/s. Given the initial velocity (Vi), final velocity (Vf), and acceleration due to gravity (g), the distance may be calculated through the equation,
                                     d = ((Vf)² - (Vi)²) / 2g
Substituting the known values,
                                     d = ((96 ft/s)² - 0))/ (2x32.2)
The value of d is 143.10 ft. 
4 0
3 years ago
Sarah, who has a mass of 55 kg, is riding in a car at 20 m/s. She sees a cat crossing the street and slams on the brakes! Her se
avanturin [10]

Answer:

-2200 N

Explanation:

The change in momentum of Sarah is equal to the impulse, which is the product between the force exerted by the seatbelt on Sarah and the time during which the force is applied:

\Delta p=I\\m \Delta v = F \Delta t

where

m is the mass

\Delta v is the change in velocity

F is the average force

\Delta t is the duration of the collision

In this problem:, we have:

m = 55 kg is Sarah's mass

\Delta v = 0-20 = -20 m/s  is the change in velocity

\Delta t = 0.5 s  is the duration of the collision

Solving for F, we find the force exerted by the seatbelt on Sarah:

F=\frac{m\Delta v}{\Delta t}=\frac{(55)(-20)}{0.5}=-2200 N

Where the negative sign indicates that the direction of the force is opposite to that of Sarah's initial velocity.

5 0
3 years ago
A 1022kg Caprice car stopped at an intersection is rear-ended by a 1620kg ranger truck moving with a speed of 14.5m/s. If the ca
Alika [10]

Answer:

Explanation:

mass of car, m = 1022 kg

mass of truck, M = 1620 kg

initial velocity of truck, U = 14.5 m/s

initial velocity of car, u = 0 m/s

Let the final velocity of car is v and the final velocity of truck is V.

Collision is elastic, so the coefficient of restitution, e = 1

Use conservation of momentum

initial momentum of car + initial momentum of truck = final momentum of car + final momentum of truck

m x u + M x U = m x v + M x V

0 + 1620 x 14.5 = 1022 v + 1620 V

23490 = 1022 v + 1620 V ..... (1)

Use the formula of coefficient of restitution

e = \frac{V_{1}-V_{2}}{u_{2}-u_{1}}

1 (14.5 - 0) = v - V

14.5 = v - V

V = v - 14.5 .... (2)

Put in equation (1)

23490 = 1022 v + 1620 (v - 14.5)

23490 = 1022 v + 1620 v - 23490

46980 = 2642 v

v = 17.8 m/s

Put in equation (2)

V = 17.8 - 14.5

V = 3.3 m/s

Thus, the speed of car is 17.8 m/s and the velocity of truck is 3.3 m/s after collision.

8 0
3 years ago
Могут ли быть сообщающиеся сосуды неодинаковы пр своей форме
Rudik [331]

Answer:

no

Explanation:

they cannot because they contain the same amount of liquid

8 0
3 years ago
Read 2 more answers
A parallel-plate capacitor has square plates that have edge length equal to 1.20×102cm and are separated by 1.00 mm. It is conne
lora16 [44]

Answer:

Energy stored in the capacitor will be 1.835\times 10^{-6}J

Explanation:

We have given edge length of capacitor = 1.2\times 10^2cm=1.2m

So area A = 1.2×1.2 = 1.44 m^2

Separation is given as d  1 mm = 10^{-3}m

We know that capacitance is given by C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 1.44}{10^{-3}}=12.744\times 10^{-9}F

Voltage is given as V = 12 volt

We know that energy stored is given by E=\frac{1}{2}CV^2=\frac{1}{2}\times 12.744\times 10^{-9}\times 12^2=1.835\times 10^{-6}J

3 0
3 years ago
Read 2 more answers
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