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Alekssandra [29.7K]
3 years ago
7

The mass of the Sun is 2 × 1030 kg, and the mass of Saturn is 5.68 × 1026 kg. The distance between Saturn and the Sun is 9.58 AU

. Veronica is solving the following equation to calculate the orbital period of Saturn, but there is an error in the equation. T = What should Veronica change to correct the equation? change the position of 2 x 1030 kg and 9.58 AU change 2 x 1030 kg to 5.68 x 1026 kg change the square root to a cube root change 9.58 AU to the distance in meters
Physics
2 answers:
GREYUIT [131]3 years ago
5 0
Not the answer but the answer will nit be  B. hope yall find the answer
USPshnik [31]3 years ago
5 0

The correct answer is D.

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A high ____will have a short wavelength.​
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Question:

A high ____will have a short wavelength

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If I were to transmit a radio wave in our three dimensional world could a fourth dimensional “being” be able to receive it?
Morgarella [4.7K]
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3 years ago
The work function for tungsten metal is 4.52eV a. What is the cutoff (threshold) wavelength for tungsten? b. What is the maximum
Tanya [424]

Answer: a) 274.34 nm; b) 1.74 eV c) 1.74 V

Explanation: In order to solve this problem we have to consider the energy balance for the photoelectric effect on tungsten:

h*ν = Ek+W ; where h is the Planck constant, ek the kinetic energy of electrons and W the work funcion of the metal catode.

In order to calculate the cutoff wavelength we have to consider that Ek=0

in this case  h*ν=W

(h*c)/λ=4.52 eV

λ= (h*c)/4.52 eV

λ= (1240 eV*nm)/(4.52 eV)=274.34 nm

From this h*ν = Ek+W;  we can calculate the kinetic energy for a radiation wavelength of 198 nm

then we have

(h*c)/(λ)-W= Ek

Ek=(1240 eV*nm)/(198 nm)-4.52 eV=1.74 eV

Finally, if we want to stop these electrons we have to applied a stop potental equal to 1.74 V . At this potential the photo-current drop to zero. This potential is lower to the catode, so this  acts to slow down the ejected electrons from the catode.

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