From the starting depth to the surface, the vertical distance is 35 ft.
From the surface to the peak of the jump, the vertical distance is 27 ft.
From the peak of the jump to the surface, the vertical distance is 27 ft.
From the surface to the ending depth, the vertical distance is 18 ft.
Then the total vertical distance is ...
35 ft + 27 ft + 27 ft + 18 ft = 107 ft
300 divide 1.5=200 let me know if this was helpful
Answer:
the force of attraction between the two charges is 3.55 N.
Explanation:
Given;
first charge carried by the object, q₁ = 15.5 µC
second charge carried by the q₂ = -7.25 µC
distance between the two charges, r = 0.525 m
The force of attraction between the two charges is calculated as;

Therefore, the force of attraction between the two charges is 3.55 N.
<span> it CAN be negative if you consider the velocity as "vector". It CANNOT if you consider the "numerical" velocity..</span>