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LenaWriter [7]
3 years ago
7

Plz help which this it is the digestive system

Chemistry
2 answers:
myrzilka [38]3 years ago
8 0
I honestly have no clue on this one
ira [324]3 years ago
8 0
I’m leaning towards B sorry if I’m wrong... but if I’m right mark me Brainly plzzz
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The graph shows the number of beans eaten by a random zocco. How many light red kidney beans were eaten on Day 7? How many dark
Tems11 [23]

Answer:

day 7   50  and day 8  40

Explanation:

3 0
3 years ago
Read 2 more answers
T = 409.5 K, P = 1.50 atm: V = ?L
Molodets [167]

Explanation:

T = 409.5 K, P = 1.50 atm: V = 22.4 L The ideal gas law is: PV = nRT where. P = pressure. V = volume n = number of moles.

7 0
3 years ago
If you added 45,000 calories to water that was at 25 degrees C, and the ending temperature was 35 degrees C, how much water did
user100 [1]

<u>Answer:</u>

<em>4.5 L water we have in litres (L).</em>

<em><u></u></em>

<u>Explanation:</u>

Q=m\times c \times \Delta T

where

\Delta T = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0  cal/(g℃))  

m is the mass of water

Plugging in the values  

\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times\left(35^{\circ} \mathrm{C}-25^{\circ} \mathrm{C}\right)$\\\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}$\\\\$m=\frac{45000 \mathrm{cal}}{1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}}$\\\\$m=4500 \mathrm{g}$\\\\Density of water $=\frac{\text { mass }}{\text { volume }}$

So,

Volume of water = mass/density

\\\\=\frac{4500 \mathrm{g}}{\frac{1.09}{\mathrm{mL}}}=4500 \mathrm{mL}$$

=4.5 L (Answer)

6 0
3 years ago
Name the following molecule in the image
Vesna [10]

\\ \sf{:}\longrightarrow 2,4-diethyl-2-methylpentane

4 0
2 years ago
PLEASE HELPPPP!!!!!
Likurg_2 [28]

Answer : The mass of nitric acid is, 214.234 grams.

Solution : Given,

Moles of nitric acid = 3.4 moles

Molar mass of nitric acid = 63.01 g/mole

Formula used :

\text{Mass of }HNO_3=\text{Moles of }HNO_3\times \text{Molar mass of }HNO_3

Now put all the given values in this formula, we get the mass of nitric acid.

\text{Mass of }HNO_3=(3.4moles)\times (63..01g/mole)=214.234g

Therefore, the mass of nitric acid is, 214.234 grams.


6 0
3 years ago
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