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liberstina [14]
2 years ago
15

In golf, a club is swung to hit a small ball resting on the ground. Golfer A holds his club a short distance behind the golf bal

l, swings through a small distance, and hits the ball. The ball travels a small distance. Golfer B holds his club above his shoulder, swings through a large distance, and hits the ball. The ball travels a large distance. Explain why golfer B's golf ball travels a longer distance than golfer A's by using Newton's First Law.
Chemistry
1 answer:
Studentka2010 [4]2 years ago
6 0

Answer:

golfer b had more space giving him the opportunity to gain momentum and strength to strike the ball

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How many Liters of 0.50M HCl are needed to neutralize 0.050L of 0.101M Ba(OH)2?
Aleksandr-060686 [28]

Answer:

V_{HCl}=5.05x10^{-3}L

Explanation:

Hello,

In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

2*n_{HCl}=n_{Ba(OH)_2}

In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

2*M_{HCl}V_{HCl}=M_{Ba(OH)_2}V_{Ba(OH)_2}\\\\V_{HCl}=\frac{M_{Ba(OH)_2}V_{Ba(OH)_2}}{2M_{HCl}} =\frac{0.101M*0.050L}{2*0.50M} \\\\V_{HCl}=5.05x10^{-3}L

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8 0
3 years ago
Read 2 more answers
Balanced nuclear equation forces the alpha decay Po-210
Serjik [45]

Answer:

_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}

Explanation:

Your unbalanced nuclear equation is:

_{84}^{210}\text{Po} \longrightarrow \, _{x}^{y}\text{Z} + \, _{2}^{4}\text{He}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

 84 = x + 2, so x =  84 - 2 =   82

210 = y + 4, so y = 210 - 4 = 206

Element 82 is lead, so the nuclear equation becomes

_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}

8 0
3 years ago
A specific brand of gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-gpiece. How many kilograms of dietary fa
Genrish500 [490]

Answer:  0.14 kg

Explanation:

Gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-g piece

That is 1 piece of candy weighs 22.7 g and contains 7.00 g of dietary fat

Converting the mass in pounds to kg  

1 lb = 0.45 kg = 450 grams    (1kg=1000g)

Number of pieces = \frac{450}{22.7g}=20pieces

1 piece contains = 7 g of dietary fat

Thus 30 pieces would contain =\frac{7}{1}\times 20=140g of dietary fat

1 g = 0.001 kg

Thus 140 grams =\frac{0.001}{1}\times 140=0.14kg

Thus 0.14 kg of dietary fat are in a box containing 1.00 lb of candy.

5 0
3 years ago
Assuming that the solubility of radon in water with 1 atm pressure of the gas over the water at 30 ∘C is 7.27×10−3M, what is the
Daniel [21]

Answer:

K = 137.55 atm/M.

Explanation:

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<em>P = (K)(C)</em>

where P is the partial pressure of the gaseous  solute above the solution (P = 1.0 atm).

k is a constant (Henry’s constant).

C is the concentration of the dissolved gas (C = 7.27 x 10⁻³ M).

∴ K = P/C = (1.0 atm)/(7.27 x 10⁻³ M) = 137.55 atm/M.

4 0
3 years ago
Unlabeled atoms joined to carbon atoms, which are not directly part of a ring structure, are assumed to be oxygen atoms.
N76 [4]
The statement above is FALSE.
Unlabeled atom joined to carbon atoms which are not directly part of a ring structure are assumed to be CARBON ATOMS. In a ring structure, an unlabeled atom at the angle where two lines joined together is always assumed to be a carbon atom<span />
3 0
3 years ago
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