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slega [8]
2 years ago
5

There are two varieties in a population of squirrels: short tails and long tails. Long-tailed squirrels are better at jumping an

d balancing in trees. Scientists observe that over the span of 100 years, the proportion of the population with long tails increases from 10% to 60%. Which statement is most likely? (1 point)
The proportion of long-tailed squirrels may have increased due to a decrease in trees.

The proportion of short-tailed squirrels may have decreased due to an increase in trees.

The proportion of short-tailed squirrels may have decreased due to decreased food availability.

The proportion of long-tailed squirrels may have increased due to increased food availability.
Chemistry
1 answer:
Ymorist [56]2 years ago
3 0

The proportion of long-tailed squirrels may have increased due to increased food availability.


The statement has it that the percentage of long tailed increased also that the long tailed are better at jumping and balancing on trees.

The first option could is tempting but saying decrease in trees would not likely support the argument.

The last option has more sound options as more food availability may lead to population increment


Hope it helps....

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2 moles of sodium chloride are dissolved in 8 liters of water. What is its molarity (M) ?
otez555 [7]

Answer:

0.25M

Explanation:

Since molarity is defined as the amount of substance in 1 liter of a solution, and amount in chemistry refers to the number of moles, molarity can be found using the equation below:

Molarity= number of moles ÷ volume in liters

Given: number of moles= 2

Volume= 8L

∴ Molarity of NaCl

= 2 ÷8

= 0.25M

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8 0
3 years ago
How many milliliters of 0.200 m fecl3 are needed to react with an excess of na2s to produce 1.38 g of fe2s3 if the percent yield
ahrayia [7]
<span>Answer: 100 ml
</span>

<span>Explanation:


1) Convert 1.38 g of Fe₂S₃ into number of moles, n


</span>i) Formula: n = mass in grass / molar mass
<span>
ii) molar mass of </span><span>Fe₂S₃ =2 x 55.8 g/mol + 3 x 32.1 g/mol = 207.9 g/mol
</span>

iii) n = 1.38 g / 207.9 g/mol = 0.00664 moles of <span>Fe₂S₃
</span>

<span>2) Use the percent yield to calculate the theoretical amount:
</span>

<span>65% = 0.65 = actual yield/ theoretical yield =>


</span>theoretical yield = actual yield / 0.65 = 0.00664 moles / 0.65 = 0.010 mol <span>Fe₂S₃</span><span>

3) Chemical equation:
</span>

<span> 3 Na₂S(aq) + 2 FeCl₃(aq) → Fe₂S₃(s) + 6 NaCl(aq)


4) Stoichiometrical mole ratios:
</span>

<span>3 mol Na₂S : 2 mol FeCl₃ : 1 mol Fe₂S₃ : 6 mol NaCl


5) Proportionality:


</span>2moles FeCl₃ / 1 mol Fe₂S₃ = x / 0.010 mol Fe₂S₃
<span>
=> x = 0.020 mol FeCl₃


6) convert 0.020 mol to volume
</span>

<span>i) Molarity formula: M = n / V
</span>

<span>ii) V = n / M = 0.020 mol / 0.2 M = 0.1 liter = 100 ml
</span>

3 0
3 years ago
Read 2 more answers
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