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jasenka [17]
3 years ago
14

Consider two positively charged particles, one of charge q0 (particle 0) fixed at the origin, and another of charge q1 (particle

1) fixed on the y-axis at (0,d1,0). What is the net force F⃗ on particle 0 due to particle 1?
Physics
1 answer:
charle [14.2K]3 years ago
8 0

Answer:

F12= (kq1q2/r12 squared)*e12

Explanation:

F12→ is the force q 1 makes on q 2 and e12 is the unit vector from q1 toward q2.

You might be interested in
in a circuit with two resistors in parallel, which of the following pair applies? a. V and I both increase across both resistors
makvit [3.9K]

The wording of the choices is really unclear.  With two resistors in parallel,
here's the situation:

-- The voltage across each resistor is the same as the voltage across
the other one.  If the parallel combination is connected to the battery,
then the voltage across each resistor is the full battery voltage.

-- The current through each resistor is (V) / (the resistance of that resistor).
That's the same current as would flow through that resistor if the other one
were not there.

-- As long as the battery or other power supply holds out, neither of these
quantities changes.

Can you match this situation to one of the choices listed ?
It looks to me as if choice 'C' is the one that's most likely
trying to say this.


6 0
4 years ago
A 85-kg astronaut is stranded from his space shuttle. He throws a 1-kg hammer away from the shuttle with a velocity of 17 m/s. H
algol [13]

Answer:

0.2 m/s

Explanation:

given,

mass of astronaut, M = 85 Kg

mass of hammer, m = 1 Kg

velocity of hammer , v =17 m/s

speed of astronaut, v' = ?

initial speed of the astronaut and the hammer be equal to zero = ?

Using conservation of momentum

(M + m) V = M v' + m v

(M + m) x 0 = 85 x v' + 1 x 17

85 v' = -17

  v' = -0.2 m/s

negative sign represent the astronaut is moving in opposite direction of hammer.

Hence, the speed of the astronaut is equal to 0.2 m/s

4 0
3 years ago
12. your friend with great excitement tells you about his newest idea to solve the energy crisis: he wants to use an electromoto
mixas84 [53]
I would tell him, in the kindest, most gentle way I could manage,
to fahgeddaboudit. 

The total amount of energy doesn't change.  Energy is never created,
and it never disappears.  If you have some energy, then it had to come
from somewhere, and if you used some energy, then it had to go
somewhere. 

You can never get more energy out of the electromotor than you put into it,
 and in the real world, you can't even get THAT much out, because some
of it is always used on the way through.

Pour yourself a cold glass of soda, then look up "Perpetual Motion" or
"Free Energy" on the internet, relax, and enjoy the show.  They are all
fakes.  They may not all be intentionally meant to fool you, but they are
all impossible.
4 0
3 years ago
Read 2 more answers
Which of these words describes humans
MA_775_DIABLO [31]
Human are eurkaryotic.  Eukaryotes are organisms that have cells with a nucleus.  Prokayotes are cells without a nucleus.  Protists are eukaryotic but they are usually single cellular. Also, human are not fungus.  Fungus cannot move and have to get food from its surrounding area.
3 0
3 years ago
A person has legs of length L = 1.10 m. (a) If the maximum angle between the legs during walking is ϕ = 50o , what is the person
vampirchik [111]

Answer:

a). Maximum Length L=0.929m

b). T=0.83 Hz or 1.2s

c). Longer, the effortless waling T=2.1 Hz or t=0.475s

d). t=1.2s V=0.774 \frac{m}{s}

t=0.475s V=1.95 \frac{m}{s}

Explanation:

Length legs=L=1.1m

angle=50

the step that give the person forms a triangle whose two sides are known and the angle that forms between them, then using trigonometry as the image

Divide the original triangle in two and form a right triangle so the angle is 25 and the L is hypotenuse and the opposite is the step length

a).

sin(\alpha) =\frac{op}{h}

op=h*sin(\frac{\alpha }{2})\\ op=1.1m*sin(\frac{50}{2})\\op=0.464m

Length of the step

L=0.464m*2

L=0.928m

b).

period=T

T=\frac{1}{time}=\frac{1}{t}\\ T=\frac{1}{1.2s}\\T=0.83 s^{-1}\\ T=0.83Hz

c).

T1=2\pi *\sqrt{\frac{L}{g}} \\T1=2\pi *\sqrt{\frac{1.1m}{9.8\frac{m}{s^{2}}}}\\ T1=2.1 Hz

The period is the inverse of the time of the motion so, the T1 is faster that the T because

t=\frac{1}{T1}=t= \frac{1}{2.1}=0.47s

d).

The speed is the relation between the distance with time so:

Vt=\frac{0.928m}{1.2s} \\Vt=0.773 \frac{m}{s} \\Vt=\frac{0.928m}{0.475s} \\Vt=1.953 \frac{m}{s}

3 0
3 years ago
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