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Vadim26 [7]
3 years ago
15

Four wire AB,BC,CD and DA each resistance 4 ohm and a fifth wire BD of resistance 8 ohm are joined to form a rectangle to which

BD is a diagonal.The effective resistance between the points A and B is?
Physics
1 answer:
Anarel [89]3 years ago
4 0
Since it's so late, and it's way past my bedtime, and I'm tired and hungry,
and I still have real work to do, and I don't think you're really a legitimate
asker of Brainly questions anyway, I'm going to do something that's against
my principles and I almost never do.  I'm going to violate my own personal
Prime Directive, and give you the answer without any explanation of where
it comes from.

Ready ?

Here goes:

The effective resistance between points 'A' and 'B' is (2 and 2/3) Ω .
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A wave pulse travels down a slinky. The mass of the slinky is m = 0.87 kg and is initially stretched to a length L = 6.8 m. The
Ber [7]

Answer:

1. v=14.2259\ m.s^{-1}

2. F_T=25.8924\ N

3. \lambda=29.6373\ m

Explanation:

Given:

  • mass of slinky, m=0.87\ kg
  • length of slinky, L=6.8\ m
  • amplitude of wave pulse, A=0.23\ m
  • time taken by the wave pulse to travel down the length, t=0.478\ s
  • frequency of wave pulse, f=0.48\ Hz=0.48\ s^{-1}

1.

\rm Speed\ of\ wave\ pulse=Length\ of\ slinky\div time\ taken\ by\ the\ wave\ to\ travel

v=\frac{6.8}{0.478}

v=14.2259\ m.s^{-1}

2.

<em>Now, we find the linear mass density of the slinky.</em>

\mu=\frac{m}{L}

\mu=\frac{0.87}{6.8}\ kg.m^{-1}

We have the relation involving the tension force as:

v=\sqrt{\frac{F_T}{\mu} }

14.2259=\sqrt{\frac{F_T}{\frac{0.87}{6.8}} }

202.3774=F_T\times \frac{6.8}{0.87}

F_T=25.8924\ N

3.

We have the relation for wavelength as:

\lambda=\frac{v}{f}

\lambda=\frac{14.2259}{0.48}

\lambda=29.6373\ m

8 0
3 years ago
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