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Alex787 [66]
3 years ago
8

A ball is thrown horizontally from the roof of a building 7.8 m tall and lands 9.5 m from the base. what was the ball's initial

speed
Physics
1 answer:
spin [16.1K]3 years ago
5 0
173 was the initial speed
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A bullet traveling at 350 m/s hits a tree, penetrating 0.125 m into the tree before stopping. The mass of the bullet is 0.200 kg
Sloan [31]

Answer:

-4.9\cdot 10^5 m/s^2

Explanation:

The motion of the bullet is a uniformly accelerated motion, therefore we can find its acceleration by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the bullet in this problem:

u = 350 m/s is the initial velocity of the bullet

v = 0 is the final velocity (the bullet comes to a stop)

s = 0.125 m is the stopping distance of the bullet

Therefore, by solving the equation for a, we find its acceleration:

a=\frac{v^2-u^2}{2s}=\frac{0^2-350^2}{2(0.125)}=-4.9\cdot 10^5 m/s^2

And the negative sign tells that the direction of the acceleration is opposite to that of the velocity.

7 0
4 years ago
A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
n200080 [17]

Answer:

a) 4.9 s

b) 167.8 m

Explanation:

Hello!

To solve this question we need to make use of the equations of motion of both the motorcycle xm(t) and the car xc(t) at t=5

Let us consider the position of the motorcycle at t=5 as the origin, that is:

xm(t+5) = vt + (1/2)at^2

xc(t+5) = vt + 60 m

where v = 22.0m/s  and   a=5m/s^2

We are looking for the time t' when the position of the car and the motorcycle are the same:

xm(t'+5)=xc(t'+5)

vt' + (1/2)at'^2 = vt' +60m

t' = √(120 m /a) = 4.89898... s

Since we are considering the origin of the cooordinate system at the position when the motorcycle starts to accelerate, the distance travelled by the motorcycle until it catches the car is given by:

xm(t'+5)= vt' + (1/2)at'^2

xm(9.89898s) = (22 * 9.89898 + 2.5 * 9.89898^2)m

xm(9.89898s)= 167.777... m

3 0
3 years ago
A small convex mirror is placed 60 cm from the pole and on the axis of a large concave mirror of radius of curvature 200 cm. The
umka2103 [35]

Answer:

Calculate 'R' of convex mirror and height of the real image

the radius of the convex mirror is 48cm

Explanation:

Distance between convex and concave mirror is =60cm

Radius of the concave mirror (R) = 200cm

For the concave mirror, u = ∞

V = {R}/{2}=100cm

The object for the convex mirror and the final image is on the pole of the concave mirror, and distance between convex and concave mirror is 60cm

u_1=60-100 =-40cm

Object will be behind the convex mirror

1/f=1/40+1/60  

f=24cms

the radius of the convex mirror is 48cm

6 0
3 years ago
Physics Homework
katrin2010 [14]

Explanation:

a. Average speed = distance / time

= 100 m / 70 s

= 1.43 m/s

b. Average displacement = displacement / time

= 0 m / 70 s

= 0 m/s

Distance is the length of the path traveled.  Displacement is the difference between the final position and initial position.

4 0
4 years ago
The question are in the picture plz help
Tanzania [10]
3) The force of Gravity no longer works, aka you lose gravity.
4) What are the ideas? I can't see them.
4 0
4 years ago
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