W=1/2cvsqr....1/2*25*10^-6*144
0.0000125*144=0.0018=18micro farad
Answer:
Displacement from the starting position is 1224m
Explanation:
The object is moving at 120 meters per second, it does this for 10.2 seconds. Use multiplication to find the answer.
Answer:
Explanation:
Given that,
Hot reservoir temperature is
TH = 58°C
TH = 58 + 273 = 331 K
Cold reservoir temperature
TC = -17°C
TC = -17°C + 273 = 256K
In 24minutes 590 J of heat was removed from hot reservoir
t = 24mins
t = 24 × 60 = 1440 seconds
Then,
Power is given as
P = E / t
P = 590 / 1440
P = 0.41 W
Since this removed from the hot reservoir, then, QH = 0.41W
We want to find heat expelled to the cold reservoir QX
Efficiency is given as
η = 1 - TH/TC = 1 - QH/QC
1 - TH/TC = 1 - QH/QC
TH/TC = QH/QC
Make QC subject of formula
QC = QH × TC / TH
QC = 0.41 × 256 / 331
QC = 0.317 W
<span>A Landsat satellite records reflected wavelengths from Earth's surface<span /></span>
It is the very last answer
