1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aev [14]
3 years ago
12

A physics student looks into a microscope and observes that small particles suspended in water are moving about in an irregular

motion. Which of the following statements is the best explanation for this observation?
a. water molecules strike the particles giving them the same average kinetic energy as the water
b. the particles are carried by convection currents in the water
c. the small particles may be considered a fluid; and thus, move about randomly
d. the actual motion is regular, but the speeds of particles are too large to observe the regular motion
e. the particles are moving to be uniformly distributed throughout the volume of the water
Physics
1 answer:
Dominik [7]3 years ago
6 0

Answer:

d. the actual motion is regular, but the speeds of particles are too large to observe the regular motion

Explanation:

The speeds of the particles are very large and comparatively the average  free path is very small . Therefore time taken in covering the free path ( path between two consecutive collision with medium particles ) is very small . Hence the st line  path covered by particles between two collision is less likely to be visible. Hence motion appears irregular or zig-zag.

You might be interested in
In searching the bottom of a pool at night, a watchman shines a narrow beam of light from his flashlight, 1.3 m above the water
kotykmax [81]
My work for your question

3 0
4 years ago
The discovery of Uranus________.
Yuki888 [10]
I think disproved geocentric theory proved that planetary orbits are elleptical
3 0
3 years ago
Read 2 more answers
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 39 m in front of you. Your reaction tim
miss Akunina [59]

Answer:

a) 10.8 m

b) 24.3 m/s

Explanation:

a)

  • In order to get the total distance traveled since you see the deer till the car comes to an stop, we need to take into account that this distance will be composed of two parts.
  • The first one, is the distance traveled at a constant speed, before stepping on the brakes, which lasted the same time that the reaction time, i.e., 0.5 sec.
  • We can find this distance simply applying the definition of average velocity, as follows:

       \Delta x_{1} = v_{1o} * t_{react} = 20 m/s * 0.5 s = 10 m (1)

  • The second part, is the distance traveled while decelerating at -11 m/s2, from 20 m/s to 0.
  • We can find this part using the following kinematic equation (assuming that the deceleration keeps the same all time):

       v_{1f} ^{2}  - v_{1o} ^{2} = 2* a* \Delta x  (2)

  • where v₁f = 0, v₁₀ = 20 m/s, a = -11 m/s².
  • Solving for Δx, we get:

       \Delta x_{2} = \frac{-(20m/s)^{2}}{2*(-11m/s)} = 18.2 m (3)

  • So, the total distance traveled was the sum of (1) and (3):
  • Δx = Δx₁ + Δx₂ = 10 m + 18.2 m = 28.2 m (4)
  • Since the initial distance between the car and the deer was 39 m, after travelling 28.2 m, the car was at 10.8 m from the deer when it came to a complete stop.

b)

  • We need to find the maximum speed, taking into account, that in the same way that in a) we will have some distance traveled at a constant speed, and another distance traveled while decelerating.
  • The difference, in this case, is that the total distance must be the same initial distance between the car and the deer, 39 m.
  • ⇒Δx = Δx₁ + Δx₂ = 39 m. (5)
  • Δx₁, is the distance traveled at a constant speed during the reaction time, so we can express it as follows:

       \Delta x_{1} = v_{omax} * t_{react} = 0.5* v_{omax} (6)

  • Δx₂, is the distance traveled while decelerating, and can be obtained  using (2):

        v_{omax} ^{2} = 2* a* \Delta x_{2} (7)

  • Solving for Δx₂, we get:

       \Delta x_{2} = \frac{-v_{omax} ^{2} x}{2*a}  = \frac{-v_{omax} ^{2}}{(-22m/s2)} (8)

  • Replacing (6) and (8) in (5), we get a quadratic equation with v₀max as the unknown.
  • Taking the positive root in the quadratic formula, we get the following value for vomax:
  • v₀max = 24.3 m/s.
6 0
3 years ago
7) the observation deck of the Empire State Building is 381 m above the street. Determine the
Elan Coil [88]

Answer:

Questions involving accelerating objects, including those in free fall, can be solved using three equations

 

y =  1/2at2 + v0t + y0

 

v = v0 + at

 

vf2 = v02 + 2 a (y - y0)

 

In this case, only the first equation is needed.

 

Since the object is falling the final height is 0 meters, the initial height is 370 m, and the acceleration is -9.8ms-2

 

Since the object is dropped, the initial velocity is 0.

 

0 = 1/2(-9.8)t2 + 370.    t = sqrt(370/4.9) = 8.69 s

Explanation:

8 0
4 years ago
Read 2 more answers
Which statement describes the chemical property of gold that results in its
LiRa [457]

Answer:

D. It is relatively inert.

Explanation:

8 0
4 years ago
Other questions:
  • Read the excerpt from a rumor of war. the tedium was occasionally relieved by a large-scale search-and-destroy operation, but th
    13·2 answers
  • Describe three physical changes that occur in nature?
    7·2 answers
  • A cubical water tank with edges measuring 10 feet in length is initially full of water. If the tank were then to lose water at a
    7·1 answer
  • Conjecture: The population of White is 80% of the total population.
    9·1 answer
  • Buckets and a Pulley Two buckets of sand hang from opposite ends of a rope that passes over an ideal pulley. One bucket is full
    6·1 answer
  • Let C be between D and E. Use the segment addition postulate to solve for V.
    13·1 answer
  • Describe what’s going on in position-time graphs 1 , 3, &5
    10·1 answer
  • A car starts from rest with an acceleration of 8 m/s/s for a time of 4 s. What was the car's final velocity?
    11·1 answer
  • It takes 444 newton to acceleration an object 7.0 m/s^2. What force was applied to the object?
    12·1 answer
  • When an object is balanced about a pivot, the total clockwise moment must be equal to the total __________ __________. What two
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!