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meriva
4 years ago
6

A person observing a flame is interested in the types of electromagnetic waves with slightly shorter and slightly longer wavelen

gths than visible light. What are these waves?
Physics
1 answer:
Nadya [2.5K]4 years ago
3 0

Answer:

Ultra violet rays and infrared rays

Explanation:

The electromagnetic radiation in the order of increasing wavelength is given as

Gamma rays

X rays

Ultra violet rays

Visible radiation

Infrared rays

Microwaves

radiowaves

So, the radiations having wavelength more than the visible radiation are infrared radiations and the radiations which having the wavelength less then the visible radiation is Ultraviolet rays.

So, we observe ultra violet radiations and infrared radiations.

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Answer:

521 nm

Explanation:

Given the values and units we are given, I'm assuming  5.76*10^14 Hz is frequency.

The formula to use here is λ * υ = c, where λ is wavelength, υ is frequency, and c is the speed of light.

λ = \frac{3*10^8\frac{m}{s} }{5.76*10^{14}Hz} = {5.20833*10^{-7} m}\approx{521 *10^{-9}m}={521 nm}

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