Answer: 12.0 m/s^2
Explanation:
Let be the angular acceleration of the end of the rod
Taking torque about the link, we have:
Torque is also given in terms of moment of inertia of the rod and its angular acceleration i.e.
From equations (i) and (ii) we have:
The acceleration of the end of the rod farthest from the link is given by:
Answer:
The distance and average speed are 54.79 m and 10.85 m.
Explanation:
Given that,
Speed = 21.7 m/s
Time = 5.05 s
(a). We need to calculate the distance
Firstly we will find the acceleration
Using equation of motion
Where, v = final velocity
u = initial velocity
t = time
Put the value in the equation
Now, using equation of motion again
For distance,
The distance is 54.79 m.
(b). We need to calculate the average speed during this time
Where, D = total distance
T = time
Put the value into the formula
Hence, The distance and average speed are 54.79 m and 10.85 m.