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Vlad1618 [11]
3 years ago
11

If the copper is drawn into wire whose diameter is 6.50 mm, how many feet of copper can be obtained from the ingot? the density

of copper is 8.94 g/cm3
Physics
1 answer:
Kobotan [32]3 years ago
6 0
Assume that an ingot of copper has a mass of 9.1 kg or 9100 g.

The cross-sectional area of the copper wire with diameter of 6.5 mm (or 0.65 cm) is
A = (π/4)*(0.65 cm)² = 0.3318 cm²

The density of copper is given as 8.94 g/cm³.
If the length of copper wire is L cm, then 
(0.3318 cm²)*(L cm)*(8.94 g/cm³) = 9100 g
L = 9100/(0.3318*8.94) = 3.0678 x 10³ cm

Note that
1 cm = 1/2.54 in = 1/2.54 in = 0.3937 in
        = 0.3937/12 = 0.03281 ft

Therefore
L = (3.0678 x 10³ cm)*(0.03281 ft/cm) = 100.65 ft

Answer: 100.65 ft

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