All categories

3 years ago

Who can do my worksheet for me

Physics

1 answer:

timurjin [86]3 years ago

5 0

Answer:

what is it on? like name one of the questions

Explanation:

You might be interested in

Why does increasing the number of trials increase confidence in the results of the experiment?

Paladinen [302]

It increases confidence because the more times you conduct the same experiment over and over should either prove your hypothesis right and wrong and eliminate any random occurrences that might affect your results.

8 0

3 years ago

Read 2 more answers

What is the effect of temperature on the solubility of a solid in a liquid? Check all correct elements that you included in your

Naddik [55]

Answer:

materials: solid dissolved in a liquid

independent variable: temperature

Explanation:

I got it right

6 0

3 years ago

The scale on the horizontal axis is 9 s per division and on the vertical axis 9 m per division

igomit [66]

Answer:

Explanation:

X axis says any of its values should be multiplied by 9sec. So you would multiply 3 and 9 which gets you 27. Pretty Easy.

5 0

4 years ago

An electromagnet is a device in which moving electric charges (current) in a coil of wire create a magnet. what’s one advantage

Vesna [10]

D.

Electromagnets are easier to control due to this feature.

3 0

3 years ago

Read 2 more answers

Consider a tall building located on the Earth's equator. As the Earth rotates, a person on the top floor of the building moves f

Irina18 [472]

Answer:

$x=\frac{2h(\omega R)^{2}}{g}$

Explanation:

When the object fall from the top floor it moves with parabolic motion.

This particular case is a horizontal motion of a projectile, so the equation that relates the distance and the time in the y-axes is:

$y=y_{0}+v_{0y}-0.5gt^{2}$

Here: y is the final height, it will be 0, because the object touch the ground.

y₀ is the initial height, it will be h and v₀ in y-axis is zero, because it has a horizontal initial velocity.

So we have:

$0=h+0-0.5gt^{2}$

$h=0.5gt^{2}$ (1)

We know that the velocity at the x-axes remains constant, then we have:

$v_{0x}=\frac{x}{t}$

x is the distance from the base of the building

we can solve it for t and put on (1).

$t=\frac{x}{v_{0x}}$

$h=0.5g\left(\frac{x}{v_{0x}}\right)^{2}$

Solving it for x we will have:

$x=\frac{2hv_{0x}^{2}}{g}$

But $v_{0x}=\omega R[\tex]R is the distance from the center of the earth to the top of the building.ω is the angular speed of the earth.Finally:[tex]x=\frac{2h(\omega R)^{2}}{g}$

I hope it helps you!

4 0

4 years ago