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Crank
2 years ago
7

What's the airplane velocity when it flies 100 miles in 20 seconds​

Physics
2 answers:
Allushta [10]2 years ago
3 0

Answer : 5m/s

Explanation:the formular for velocity is distance /time or you can say displacement /time. Then it would then be

100/20 =5m/s

Lisa [10]2 years ago
3 0

Speed = distance / time

The airplane's speed is

(100 miles) / (20 seconds)

That's 26,400 feet per second,

5 miles per second,

300 miles per minute,

18,000 miles per hour.

There's not enough information to describe the airplane's velocity. For that, you need to know what direction it's flying.

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If the angle of reflection is 25 degrees, the angle of incidence is
natali 33 [55]

Answer:

25 degrees

Explanation:

The angle of incidence equals the angle of reflection

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3 years ago
The number line shows the starting and ending velocities for ball 1. What’s the change in velocity of ball 1? Calculate the valu
djverab [1.8K]

Answer:

The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.

The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds

5 0
3 years ago
Read 2 more answers
Suppose that a star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen bu
ladessa [460]

Answer:

It can be concluded that the star is moving away from the observer.

Explanation:

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving  toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).

The wavelength at rest for this case is 434 nm and 410 nm (\lambda_{0} = 434nm, \lambda_{0} = 410nm)

Redshift: \lambda_{measured}  >  \lambda_{0}

Blueshift: \lambda_{measured}  <  \lambda_{0}

Since, \lambda_{measured} (444nm) is greater than \lambda_{0} (434 nm) and \lambda_{measured} (420nm) is greater than \lambda_{0} (410 nm), it can be concluded that the star is moving away from the observer

6 0
3 years ago
Compare and contrast the gravitational and electric forces.
Olin [163]

Answer:   Idk I think I forgot

Explanation:

4 0
3 years ago
A 9 newtwon charge is Felt on a (1x10^-4) C charge from another charge that is 3 meters away. What is the magnitude of that othe
Marina86 [1]

The magnitude of that other charge will be 9×10⁻⁵ C. The force on the charge is inverse of the distance.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The magnitude of that other charge is found as;

\rm F = \frac{Kq_1q_2}{r^2} \\\\ \rm 9  = \frac{9 \times 10^9 \times 1\times 10^{-4}\times q_2}{(3)^2} \\\\ q_2=9\times 10^{-5} \ C

Hence, the magnitude of that other charge will be 9×10⁻⁵ C.

To learn more about Columb's law, refer to the link;

brainly.com/question/1616890

#SPJ1

6 0
2 years ago
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