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3 years ago

6

Gregory draws a scale drawing of his room. The scale that he uses is 1 cm : 4 ft. On his drawing, the room is 3 centimeters long

. Which equation can be used to find the actual length of Gregory's room?

1 answer:

Airida [17]3 years ago

7 0

3cm x 4ft. your answer should be wrote in fr

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A school district is considering moving the start of the school day at Groveland High from 8:00 a.m. to 9:00 a.m. to allow stude

DaniilM [7]

Answer:

The answer is " $\bold{(7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} }\\\\$ "

Step-by-step explanation:

Given values:

$\bar{x_1}=7.1\\\\\bar{x_2}=8.3\\\\s_1=1.7\\\\s_2=1.9\\\\n_1=50\\\\n_2=39$

Using formula:

$\to (\bar{x_1} -\bar{x_2}) \pm t \sqrt{\frac{(s_1)^2}{n_1}+\frac{(s_1)^2}{n_2}} \\\\$

Put the values in the above formula:

$\to (7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} \\\\$

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3 years ago

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Archy [21]

The value of integration of y=16- $x^{2}$ from x=-1 to x=1 is 94/3.

Given the equation y=16- $x^{2}$ and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16- $x^{2}$ from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16- $x^{2}$

Find the integration of 16- $x^{2}$ .

=16x- $x^{3}/3$

Now find the value of integration from x=-1 to x=1.

=16(1)- $(1)^{3}/3$ -16(-1)- $(-1)^{3}/3$

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

=94/3

Hence the value of integration of y=16- $x^{2}$ from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

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1 year ago

A dependent system of equations is a system with __________.

andre [41]

The same line is written in two different forms

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3 years ago

Lacey measured a community college and made a scale drawing. She used the scale 3 millimeters : 2 meters. A building at the coll

Artyom0805 [142]

Answer: Rafi measured a summer camp and made a scale drawing. The scale he used was 1 millimeter = 3 meters. The sand volleyball court is 6 millimeters in the drawing.

Step-by-step explanation:

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2 years ago

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Nutka1998 [239]

Answer:

(C) Maria's elevation increased between 9:00 and 12:00

Step-by-step explanation:

Looking at the graph, we can test each statement.

For A, it says Maria's elevation remained constant for 2 hours. Looking at the graph, we can see that it remained constant for just one hour, so this is eliminated.

For B, Maria's elevation decreased between 1:00 and 3:00, we can see that while x is between 1:00 and 3:00, the y is decreasing, meaning this statement is false - this is eliminated.

For C, Maria's elevation increased between 9:00 and 12:00, we can see that while x is between 9:00 and 12:00, the graph is increasing - which means this is correct.

For D, Maria spent more time decreasing her elevation than increasing, we can count how many hours were spent doing each. Comparing the x-axis, we can see that Maria spent 5 hours increasing and 3 hours decreasing, meaning that Maria spent more time INCREASING than decreasing, making this statement false.

Hope this helped!

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3 years ago