The type of bonds present in the compound. and the type of structure it has and the elements that are presents and the number of moles of each element in one mole of the compound.
The total number of atoms make up the products :
D) 1 carbon, 4 hydrogen, and 4 oxygen
<h3>Further explanation
</h3>
Complete combustion of Hydrocarbons with Oxygen will produce CO₂ and H₂O compounds.
If O₂ is insufficient there will be incomplete combustion produced by CO and H and O
Hydrocarbon combustion reactions (especially alkanes)
For combustion of methane (CH₄) and two molecules of oxygen (O₂).

The number of atoms make up the products
CO₂ : 1 carbon, 2 oxygen
2H₂O : 4 hydrogen , 2 oxygen
Answer:
A) CH3CH2CH2CH2CH2CH2OH
Explanation:
For this question, we have the following answer options:
A) CH3CH2CH2CH2CH2CH2OH
B) (CH3CH2)2CH(OH)CH2CH3
C) (CH3CH2)2CHOHCH3
D) (CH3CH2)3COH
E) (CH3CH2)2C(CH3)OH
We have to remember the<u> reaction mechanism</u> of the substitution reaction with
. <em>The idea is to generate a better leaving group in order to add a "Br" atom.</em>
The
attacks the "OH" generation new a bond to P (O-P bonds are very strong), due to this new bond we will have a better leaving group that can remove the oxygen an allow the attack of the Br atom to generating a new C-Br bond. This is made by an <u>Sn2 reaction</u>. Therefore we will have a faster reaction with <u>primary substrates</u>. In this case, the only primary substrate is molecule A. So, <em>"CH3CH2CH2CH2CH2CH2OH"</em> will react faster.
See figure 1
I hope it helps!