Answer:
126.5g
Explanation:
n=<u>m</u><u> </u>
M
where n is moles
m is mass of substance
M is molar mass
molar mass of sodium is 23g/mol
m=nM
m=5.5(23)
m=126.5
Answer:
nitrogen in atmospheres of a sample is 0.679
Answer:
28500 years
Explanation:
Applying,
A = A'()............... Equation 1
Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.
From the question,
Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.
Substitute these values into equation 1
1 = 0.0313()
= 1/0.0313
= 31.95
≈ 32
≈ 2⁵
Equating the base and solve for x
x/5700 ≈ 5
x ≈ 5×5700
x ≈ 28500 years
Answer:
Explanation:
2AgNO3 + CaCl2 ----> 2AgCl + Ca(NO3)2
Answer:
It was done correctly, Your answer is completely correct.
Explanation: