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GenaCL600 [577]
3 years ago
6

Question 8

Chemistry
1 answer:
nexus9112 [7]3 years ago
6 0
72 degrees C (minus 273)
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Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.
Misha Larkins [42]
Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

 moles HCl = moles KOH \\  \\ cHCl*vHCl=cKOH*vKOH \\  \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}=  541,54mL

So, the required volume of HCl is 541,54 mL

Have a nice day!
8 0
3 years ago
Consider a hypothetical reaction in which A and B are reactants, and C and D are products. If 26 grams of A completely reacts wi
natali 33 [55]

Answer:

The answer to your question is: 24 grams of D

Explanation:

To answer this question we need to remember the Lavoisier law of conservation of mass, which says that in a chemical reaction matter is neither created nor destroyed.

This means that the amount of matter stays the same.

Then, the reaction is

                    A      +      B      ⇒       C      +      D

                 26 g         12 g             14 g            x

mass                              

of reactants      38 g                              ?          mass of products, but it must be

                                                                          equal to the mass of products

Then                14g + x = 38

                        x = 38 - 14

                        x = 24 g of D                                                        

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3 years ago
Which of the following is not a chemistry topic?
Tju [1.3M]
I’m pretty sure it’s D
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Answer:

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<em>Hope that helps! :)</em>

<em></em>

<em>-Aphrodite</em>

Explanation:

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the earth is different in all places

Explanation:

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