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Alexus [3.1K]
2 years ago
11

25.2 mL of water are placed in a graduated cylinder. A 22.6 g stone is dropped in, and the water level rises to 32.4 mL. Find th

e stone's density.
Chemistry
1 answer:
VMariaS [17]2 years ago
5 0
<span>Displaced volume :

final volume - initial volume

32.4 mL - 25.2 mL => 7.2 mL

Density = mass / volume

D = 22.6 g / 7.2 mL

D = 3.1388 g/mL

hope this helps!</span>
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What is the molar mass of glucose, C3H603?
ziro4ka [17]

Answer:

The mass percentage of carbon can be found easily using the molar mass of C6H12O6, 180.1559 g/mol. We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass. C6H12O6 = CO2 + C3H6O3 + CH3OCH3 Take fructose for example. Compound.

Explanation: I looked it up

4 0
2 years ago
Which of the following cases earths plates to move continuously.
Murljashka [212]

The correct answer to this item is letter

C. convection in earth's mantle

Convection currents move tectonic plates when the rising mantle creates heat inside. The radioactive decay of several substances is responsible for the creation of the convection currents.

4 0
3 years ago
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What is the frequency of a photon having an energy of 4.91 × 10–17 ? (c = 3.00 × 108 m/s, h = 6.63 × 10–34 J · s)​
AlexFokin [52]

Answer:

The frequency of the photon is 7.41*10¹⁶ Hz

Explanation:

Planck states that light is made up of photons, whose energy is directly proportional to the frequency of radiation, according to a constant of proportionality, h, which is called Planck's constant. This is expressed by:

E = h*v

where E is the energy, h the Planck constant (whose value is 6.63*10⁻³⁴ J.s) and v the frequency (Hz or s⁻¹).

So the frequency will be:

v=\frac{E}{h}

Being E= 4.91*10⁻¹⁷ J and replacing:

v=\frac{4.91*10^{-17} J}{6.63*10^{-34} J.s}

You can get:

v= 7.41*10¹⁶ \frac{1}{s}= 7.41*10¹⁶ Hz

<u><em>The frequency of the photon is 7.41*10¹⁶ Hz</em></u>

<u><em></em></u>

4 0
2 years ago
Given that H2(g) + F2(g) - &gt; 2HF(g) delta H rxn = -546.6 kJ 2H2(g)+ O2(g) - &gt; 2H2O(l) delta H rxn = 571.6 kJ
olasank [31]

Answer:

ΔHrxn = -521.6 kJ

Explanation:

To do this, let's write the equations by separate:

H₂ + F₂ -------> 2HF        ΔH = -546.6 kJ

2H₂ + O₂ -------> 2H₂O   ΔH = -571.6 kJ

For these reactions, we want to get the following reaction:

2F₂ + 2H₂O -------> 4HF + O₂     ΔHrxn = ?

To do this, all we have to do is take the first two reaction and put them in the way to obtain the third reaction. When we look the final reaction we can see that the water is on the reactants, when originally it was on the product, while Florine is doubled. So all we have to do is rewrite the first two reactions, duplicate the first reaction, and reverse the second reaction, and that way we will get the final reaction:

1) (H₂ + F₂ -------> 2HF ) x2      ΔH = -546.6 kJ x 2

2) (2H₂O --------> 2H₂ + O₂)   ΔH = -571.6 kJ x -1

---------------------------------------------------------------------------

1) 2H₂ +2F₂ -------> 4HF      ΔH = -1093.2 kJ

2) 2H₂O --------> 2H₂ + O₂   ΔH = +571.6 kJ      

Now we sum 1) and 2). In this way, hydrogen cancels out and we do the same with the enthalpy:

1) 2H₂ +2F₂ -------> 4HF      ΔH = -1093.2 kJ

2) 2H₂O --------> 2H₂ + O₂   ΔH = +571.6 kJ  

---------------------------------------------------------------

2F₂ + 2H₂O -------> 4HF + O₂     ΔHrxn = -1093.2 + 571.6 = -521.6 kJ

So the enthalpy of this reaction is

<em>ΔHrxn = -521.6 kJ</em>

3 0
3 years ago
Copper (II) oxide can be heated until it decomposes into elemental copper and oxygen gas. Is 0.695 grams of Copper (II) oxide is
insens350 [35]

Answer:

0.55 g of Cu can produced by this decomposition

Explanation:

Let's think the reaction of decomposition:

2CuO → 2Cu + O₂

Ratio is 2:2. 2 moles of CuO can decompose into 2 moles of Cu and 1 mol of oxygen.

Let's convert the mass of oxyde to moles → 0.695 g. 1 mol/ 79.55 g =

8.74×10⁻³ moles

8.74×10⁻³ mol of CuO decompose to 8.74×10⁻³ moles of Cu

Let's find out the mass → 8.74×10⁻³ mol . 63.55 g/1mol = 0.55 g

4 0
2 years ago
Read 2 more answers
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