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alekssr [168]
3 years ago
10

The volume of a gas is decreased from 100 liters at 173.0°C to 50 liters at a constant pressure. After the decrease in volume, w

hat is the new temperature of the gas?
Chemistry
1 answer:
Minchanka [31]3 years ago
5 0

Answer:

223.08 K

Explanation:

First we <u>convert 173.0 °C to K</u>:

  • 173.0 °C + 273.16 = 446.16 K

With the absolute temperature we can use <em>Charles' law</em> to solve this problem:

  • T₁V₂=T₂V₁

Where in this case:

  • T₁ = 446.16 K
  • V₂ = 50 L
  • T₂ = ?
  • V₁ = 100 L

We <u>input the data</u>:

  • 446.16 K * 50 L = T₂ * 100 L

And <u>solve for T₂</u>:

  • T₂ = 223.08 K
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A 700.0 mL gas sample at STP is compressed to a volume of 200.0 mL, and the temperature is increased to 30.0°C. What is the new
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Answer: The new pressure of the gas in Pa is 388462

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

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