Question

The volume of a gas is decreased from 100 liters at 173.0°C to 50 liters at a constant pressure. After the decrease in volume, what is the new temperature of the gas?

Answer 1

Answer:

223.08 K

Explanation:

First we convert 173.0 °C to K:

• 173.0 °C + 273.16 = 446.16 K

With the absolute temperature we can use Charles' law to solve this problem:

• T₁V₂=T₂V₁

Where in this case:

• T₁ = 446.16 K

• V₂ = 50 L

• T₂ = ?

• V₁ = 100 L

We input the data:

• 446.16 K * 50 L = T₂ * 100 L

And solve for T₂:

• T₂ = 223.08 K