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2 years ago

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The volume of a gas is decreased from 100 liters at 173.0°C to 50 liters at a constant pressure. After the decrease in volume, w

hat is the new temperature of the gas?

1 answer:

Minchanka [31]2 years ago

5 0

Answer:

223.08 K

Explanation:

First we <u>convert 173.0 °C to K</u>:

173.0 °C + 273.16 = 446.16 K

With the absolute temperature we can use <em>Charles' law</em> to solve this problem:

T₁V₂=T₂V₁

Where in this case:

T₁ = 446.16 K

V₂ = 50 L

T₂ = ?

V₁ = 100 L

We <u>input the data</u>:

446.16 K * 50 L = T₂ * 100 L

And <u>solve for T₂</u>:

T₂ = 223.08 K

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