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iogann1982 [59]
3 years ago
14

A bag contains 3 green marbles, 7 blue marbles ,band 2 black marbles the probility of randomly picking a green marble

Mathematics
1 answer:
adell [148]3 years ago
5 0
First, add the total of all marbles in the bag: 3+2+7=12. this will be our denomonator. the probability is just the number of marbles in this question. there are three green marbles out of 12, and since you cannot simplify, that is your probability: 3/12
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F(x)=-3x • G(x) = x +7
kirill [66]

Answer:

-3x^2 - 21x

Step-by-step explanation:

This question is representing multiplying two functions :

We are finding f(x) * g(x)

We know that f(x) is -3x and g(x) is x + 7, therefore :

(-3x)(x + 7)

Follow FOIL :

First :

(-3x)(x)

-3x^2

Outer :

(-3x)(7)

-21x

Therefore the answer is :

-3x^2 - 21x

7 0
3 years ago
#7 I don't know how to solve this
____ [38]
30+1.95x=7.95x

so, 6x=30

x=5
3 0
2 years ago
Find the distance between Brisbane and
Lady bird [3.3K]

Answer:

30 miles

Step-by-step explanation:

So since we know the scale of the map (3 in : 15 mi) we will just have to find out how much 3 inches fits into 6 inches and then multiply the result by 15 miles. So we do the following steps.......

(\frac{6}{3} )15 = (2)(15) = 30

5 0
2 years ago
HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!! CERTAIN ANSWERS AND I WILL MARK YOU AS BRAINIEST!!!! WISH YOU BEST OF LUCK HOPEFULLY ITS N
AURORKA [14]

Answer:

1)

Minimum is a 4th Degree

2)

Positive; Even

3)

x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it <em>crosses through</em> the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph <em>bounces off</em> at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: x=-4, -1, 3

We know that it<em> passes through</em> x=-4 \text{ and } x=-1 . So, these two factors must have an odd multiplicity.

However, since the graph <em>bounces off</em> x=3, this factor must have an even multiplicity.

And we're done!

7 0
2 years ago
John gets a new job and receive a 500 signing bonus after he makes 200 a day
FromTheMoon [43]
Okay, I will start talking you through it, it'll be quick but I need your response. Just leave a comment! Loves,
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5 0
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