Answer:
m = -3, n = 1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
3m - n = -10
2m + n = -5
<u>Step 2: Solve for </u><em><u>m</u></em>
<em>Elimination</em>
- Combine equations: 5m = -15
- Divide 5 on both sides: m = -3
<u>Step 3: Solve for </u><em><u>n</u></em>
- Define equation: 3m - n = -10
- Substitute in <em>m</em>: 3(-3) - n = -10
- Multiply: -9 - n = -10
- Add 9 to both sides: -n = -1
- Divide -1 on both sides: n = 1
Answer:
31 1/3
Step-by-step explanation:
3x-10=84, given
3x=94, add 10 to both sides
x = 31 1/3, divide both by three
Let t, h, b represent the weighs of tail, head, and body, respectively.
t = 4 . . . . given
h = t + b/2 . . . . the head weighs as much as the tail and half the body
b/2 = h + t . . . . half the body weighs as much as the head and tail
_____
Substituting for b/2 in the second equation using the expression in the third equation, we have
... h = t + (h + t)
Subtracting h from both sides gives
... 0 = 2t . . . . . . in contradiction to the initial statement about tail weight.
Conclusion: there's no solution to the problem given here.
Given :
Amount of candy Jordan have , .
Amount left after giving some to brother , .
To Find :
How much did he give to his brother .
Solution :
Let , amount he gave to his brother is , b .
So ,
So , amount he give to his brother is .
Hence , this is the required solution .
You seem to have
.. g(x) = {(2x^2 -4x -16)/(x -4) . . . x ≠ 4
.. .. .. .. ..{ kx -16 . . . . . . . . . . . . . . x=4
The first expression can be simplified to
.. (2x^2 -4x -16)/(x -4) = 2(x +2)(x -4)/(x -4) = 2(x +2) . . . . x ≠ 4
At x=4, this simplified version has the value
.. 2(4 +2) = 12
To make the alternate definition of g(x) have that same value at x=4, we must have
.. k*4 -16 = 12
.. 4k = 28
,, k = 7
The constant k must be 7 for the function to be continuous at x=4.