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2 years ago

What is the net force acting on a car cruising at a constant velocity of 70 km/h (a) on a level road and (b) on an uphill road?

Engineering

1 answer:

ElenaW [278]2 years ago

4 0

Answer:

a) zero b) zero

Explanation:

Newton's first law tells us that a body remains at rest or in uniform rectilinear motion, if a net force is not applied on it, that is, if there are no applied forces or If the sum of forces acting is zero. In this case there is a body that moves with uniform rectilinear motion which implies that there is no net force.

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If a heat engine has an efficiency of 30% and its power output is 600 W, what is the rate of heat input from the combustion phas

jarptica [38.1K]

Answer:

The heat input from the combustion phase is 2000 watts.

Explanation:

The energy efficiency of the heat engine ( $\eta$ ), no unit, is defined by this formula:

$\eta = \frac{\dot W}{\dot Q}$ (1)

Where:

$\dot Q$ - Heat input, in watts.

$\dot W$ - Power output, in watts.

If we know that $\dot W = 600\,W$ and $\eta = 0.3$ , then the heat input from the combustion phase is:

$\eta = \frac{\dot W}{\dot Q}$

$\dot Q = \frac{\dot W}{\eta}$

$\dot Q = \frac{600\,W}{0.3}$

$\dot Q = 2000\,W$

The heat input from the combustion phase is 2000 watts.

8 0

2 years ago

If the channel-Length modulation effect is neglected, ID in the saturation region is considered to be independent of VDS

djverab [1.8K]

The answer is true because if the effect is neglected, the saturation id region is considered true

4 0

2 years ago

Match the types of AI to the correct automation tasks.

Maru [420]

Answer:

Theory of Mind : A robotic head has a face that recognizes and simulates emotions.

Self aware : A robot tries to protect itself from harm

Purely Reactive : A door automatically opens when a person steps in front of it.

Limited Memory : A personal assistant software tracks a persons travel routes and suggests shorter routes.

Explanation:

Artificial intelligence is simply a technology which enables automation. It enables system perform task without being explicitly controlled. Purely reactive systems do not store Data in memory, it simply observes what going on at the moment which is what it was programmed to do and takes a step. One the machine detects someone approaching up to a certain distance, it opens.

Limited Memory systems store information about the past and this enhances its Decison making, prediction engines, self driving cars use this kind of artificial intelligence.

Theory of Mind : Here, systems are trained to detect, understand and replicate what is understood. Once the robot identifies an emotion, it replicates it.

Self - Aware : An advanced level of AI, where systems will not only be able to replicate what they see, but also make conscious decisions as to which action to take in different circumstances.

5 0

3 years ago

A circuit contains a resistor, an inductor, and a capacitor. When an AC voltage is applied across the circuit, the impedance of

katen-ka-za [31]

Answer:

The impedance of the circuit depends on the angular frequency of the voltage source.

Explanation:

In a electric circuit, the magnitude of the impedance, is given by the following expression:

$Z = \sqrt{R^{2} + (Xl-Xc)^{2} (1)$

where R = Resistance

Xl = Inductive reactance = ω*L

Xc = Capacitive Reactance = 1/ωC

and ω = angular frequency of the voltage source.

So, it can be seen that the impedance depends on the value of the constants R,L and C, and on the angular frequency ω.

3 0

2 years ago

Consider an 8-car caravan, where the propagation speed is 100 km/hour, each car takes 1 minute to pass a toll both. The caravan

melamori03 [73]

Answer:

A. 36 minutes

B. 120 minutes

i. 144 minutes

ii. 984 minutes

D. Car 1 is 1.67km ahead of Cat 2 when Car 2 passed the toll B.

E. 98.33km

Explanation

Given

dAb = 10km

dBc = 10km

Propagation Speed = 100km/hr

Delay time = 1 minute

Numbers of cars = 8

Number of tolls = 3

Total End to End delay = Propagation delay + Transition delay

Calculating Propagation Delay

Propagation delay = Total Distance/Propagation speed

Total distance = 10km + 10km = 20km

So, Propagation delay = 20km/100km/hr

Propagation delay = 0.2 hour

Translation delay = delay time* numbers of tolls * numbers of cars

Transitional delay = 1 * 3 * 8

Transitional delay = 24 minutes

Total End delay = 24 minutes + 0.2 hours

= 24 minutes + 0.2 * 60 minutes

= 24 minutes + 12 minutes

= 36 minutes

Total End to End delay = Propagation delay + Transition delay

Calculating Propagation Delay

Propagation delay = Total Distance/Propagation speed

Total distance = 10km + 10km = 20km

So, Propagation delay = 20km/100km/hr

Propagation delay = 0.2 hour

Translation delay = delay time* numbers of tolls ------ Cars traveling separately

Transitional delay = 1 * 3

Transitional delay = 3 minutes

Total End delay for one car = 3 minutes + 0.2 hours

= 3 minutes + 0.2 * 60 minutes

= 3 minutes + 12 minutes

= 15 minutes

Total End delay for 8 cars = 8 * 15 = 120 minutes

Given

dAb = 100km

dBc = 100km

Propagation Speed = 100km/hr

Delay time = 1 minute

Numbers of cars = 8

Number of tolls = 3

i. Cars travelling together

Total End to End delay = Propagation delay + Transition delay

Calculating Propagation Delay

Propagation delay = Total Distance/Propagation speed

Total distance = 100km + 100km = 200km

So, Propagation delay = 200km/100km/hr

Propagation delay = 2 hours

Translation delay = delay time* numbers of tolls * numbers of cars

Transitional delay = 1 * 3 * 8

Transitional delay = 24 minutes

Total End delay = 24 minutes + 2 hours

= 24 minutes + 2 * 60 minutes

= 24 minutes + 120 minutes

= 144 minutes

ii. Cars travelling separately

Total End to End delay = Propagation delay + Transition delay

Calculating Propagation Delay

Propagation delay = Total Distance/Propagation speed

Total distance = 100km + 100km = 200km

So, Propagation delay = 200km/100km/hr

Propagation delay = 2 hours

Translation delay = delay time* numbers of tolls ------ Cars traveling separately

Transitional delay = 1 * 3

Transitional delay = 3 minutes

Total End delay for one car = 3 minutes + 2 hours

= 3 minutes + 2 * 60 minutes

= 3 minutes + 120 minutes

= 123 minutes

Total End delay for 8 cars = 8 * 123 = 984 minutes

Distance = 100km

Time = 1 min/car

Car 1 is 1 minute ahead of car 2 --- at toll A and B

If car 1 leaves toll B after 10 minutes then cat 2 leaves after 11 minutes

Time delay = 11 - 10 = 1 minute

Distance = time * speed

= 1 minute * 100km/hr

= 1 hr/60 * 100 km/hr

= 100/60

= 1.67km

Given

Distance = 100km

Distance behind = 1.67

Maximum value of dBc = 100km - 1.67km = 98.33km

The maximum distance that can be reached is 98.33km

7 0

3 years ago