A. Physical I/O sensors
Safety switches, operator inputs, travel limit switches etc
Explanation:
For true Strain:
step 1:
E true = Ln(1 + 0.5 ) = 0.40
Step 2:
E true = Ln(1 + 0.33 ) = 0.29
By single step process:
E true = Ln(1 + 1 ) = 0.69
total strain of step process = 0.40 + 0.29 = 0.69 units
SO TRUE STRAIN IS ADDITIVE.
Answer:
A.) Find the answer in the explanation
B.) Ua = 7.33 m/s , Vb = 7.73 m/s
C.) Impulse = 17.6 Ns
D.) 49%
Explanation:
Let Ua = initial velocity of the rod A
Ub = initial velocity of the rod B
Va = final velocity of the rod A
Vb = final velocity of the rod B
Ma = mass of rod A
Mb = mass of rod B
Given that
Ma = 2kg
Mb = 1kg
Ub = 3 m/s
Va = 0
e = restitution coefficient = 0.65
The general expression for the velocities of the two rods after impact will be achieved by considering the conservation of linear momentum.
Please find the attached files for the solution
Answer:
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Explanation:
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