1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ANTONII [103]
2 years ago
8

The heat required to raise the temperature of m (kg) of a liquid from T1 to T2 at constant pressure is Z T2CpT dT (1) In high sc

hool and in first-year college physics courses, the formula is usually given asQ ΔH m Q mCp ΔT mCpT2 ␣T1 (2)T1(a) What assumption about Cp is required to go from Equation 1 to Equation 2? (b) The heat capacity (Cp) of liquid n-hexane is measured in a bomb calorimeter. A small reaction flask (the bomb) is placed in a well-insulated vessel containing 2.00L of liquid n–C6H14 at T 300 K. A combustion reaction known to release 16.73 kJ of heat takes place in the bomb, and the subsequent temperature rise of the system contents is measured and found to be 3.10 K. In a separate experiment, it is found that 6.14kJ of heat is required to raise the temperature of everything in the system except the hexane by 3.10 K. Use these data to estimate Cp[kJ/(mol K)] for liquid n-hexane at T 300 K, assuming that the condition required for the validity ofEquation 2 is satisfied. Compare your result with a tabulated value.
Engineering
1 answer:
a_sh-v [17]2 years ago
6 0

Answer:

(a)

<em>d</em>Q = m<em>d</em>q

<em>d</em>q = C_p<em>d</em>T

q = \int\limits^{T_2}_{T_1} {C_p} \, dT   = C_p (T₂ - T₁)

From the above equations, the underlying assumption is that  C_p remains constant with change in temperature.

(b)

Given;

V = 2L

T₁ = 300 K

Q₁ = 16.73 KJ    ,   Q₂ = 6.14 KJ

ΔT = 3.10 K       ,   ΔT₂ = 3.10 K  for calorimeter

Let C_{cal} be heat constant of calorimeter

Q₂ = C_{cal} ΔT

Heat absorbed by n-C₆H₁₄ = Q₁ - Q₂

Q₁ - Q₂ = m C_p ΔT

number of moles of n-C₆H₁₄, n = m/M

ρ = 650 kg/m³  at 300 K

M = 86.178 g/mol

m = ρv = 650 (2x10⁻³) = 1.3 kg

n = m/M => 1.3 / 0.086178 = 15.085 moles

Q₁ - Q₂ = m C_p' ΔT

C_p = (16.73 - 6.14) / (15.085 x 3.10)

C_p = 0.22646 KJ mol⁻¹ k⁻¹

You might be interested in
Carbon resistors often come as a brown cylinder with colored bands. These colored bands can be read to determine the manufacture
alexandr1967 [171]

Answer:

a) 4.7 kΩ, +/- 5%

b) 2.0 MΩ, +/- 20%

Explanation:

a) If the resistor has the following combination of color bands:

1) Yellow = 1st digit = 4

2) Violet = 2nd digit = 7

3) Red = multiplier = 10e2

4) Gold = tolerance = +/- 5%

this means that the resistor has 4700 Ω (or 4.7 kΩ), with 5% tolerance.

b) Repeating the process for the following combination of color bands:

1)  Red = 1st digit = 2

2) Black = 2nd digit = 0

3) Green = multiplier = 10e5

4) Nothing = tolerance = +/- 20%

This combination represents to a resistor of 2*10⁶ Ω (or 2.0 MΩ), with +/- 20% tolerance.

7 0
3 years ago
Two variables, num_boys and num_girls, hold the number of boys and girls that have registered for an elementary school. The vari
Flauer [41]

Answer:

Using python

num_boys = int(input("Enter number of boys :"))

num_girls = int(input("Enter number of girls :"))

budget = int(input("Enter the number of dollars spent per school year :"))

try:

dollarperstudent = budget/(num_boys+num_girls)

print("Dollar spent per student : "+str(dollarperstudent))#final result

except ZeroDivisionError:

print("unavailable")

3 0
3 years ago
Write a statement that calls the recursive method backwardsAlphabet() with parameter startingLetter.
Tcecarenko [31]

Recursion refers to the act of calling a function itself. With the use of this strategy, complex problems can be reduced to more manageable, simpler ones. Recursion might be a little challenging to comprehend. The best method to figure out how it works is to experiment with it.

<h3>How to write a programme by recursive method ?</h3>

The process of making a function call itself is known as recursion. With the use of this strategy, complex problems can be reduced to more manageable, simpler ones. Recursion might be a little challenging to comprehend. Experimenting with it is the most effective way to learn how it functions.

public class Recursive Calls {

public static void backwards Alphabet(char currLetter) {

if (currLetter == 'a') {

System.out.println(currLetter);

}

else {

System.out.print(currLetter + " ");

backwards Alphabet(--currLetter);

}

return;

}

public static void main (String [] args) {

char starting Letter = '-';

starting Letter = 'z';

// Your solution goes here

backwards Alphabet(starting Letter);

return;

}

}

To learn more about recursive method refer to :

brainly.com/question/24167967

#SPJ4

6 0
1 year ago
X+3=2<br>x=??<br><br><br><br>No spamming​
PtichkaEL [24]

Answer:

x+3=2

x=2-3꧁

꧁꧁꧂꧂꧂꧂

x=-1

4 0
3 years ago
A steam power plant is represented as a heat engine operating between two thermal reservoirs at 800 K and 300 K. The temperature
Sergeeva-Olga [200]
Yeet is the answer .....
4 0
2 years ago
Other questions:
  • Let suppose, you are going to develop a web-application for school management system. Then what architectural pattern will you u
    9·1 answer
  • What is the capacity of the machine in batches?
    10·1 answer
  • 1. A farmer had 752 sheep and took one shot that got them all. How did he do it?
    9·1 answer
  • When will the entropy value of the universe attained its maximum value?
    13·1 answer
  • What differentiates the master builder approach prior to the Renaissance from later approaches? Projects do not depend on indivi
    14·1 answer
  • What is the chord length of an airplane called?
    14·1 answer
  • What is the normal balance side of an asset?
    9·1 answer
  • Describe in your own words the three strengthening mechanisms
    7·1 answer
  • A 50-mm cube of the graphite fiber reinforced polymer matrix composite material is subjected to 125-kN uniformly distributed com
    14·1 answer
  • What is an example of a traditional career?
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!