The speed of light in a vacuum is approximately 2.99 × 108 m/s, and the speed of light through a piece of glass is approximately
2 answers:
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Answer:
a) -1.325 μC
b) 4.17μC
Explanation:
First, you need to know that charge is conserved. So, the adition of the charges, as there is no lost in charge, should always be the same. Also, after the wire is removed, both spheres will have the same charge, trying to find equilibrium. In summary:
We know both q1f and q2f must be positive, because the negative charge at the beginning was the the smaller.
The electrostatic force is equal to:
K is the Coulomb constant, equal to 9*10^9 Nm^2/C^2
Now, we are told that the electrostatic force after the wire is equal to 0.0443 N:
Originally, the force is negative because it was an attraction force, therefore, its direction was opposite to the direction of the repulsive force after the wire:
Solving the quadratic equation:
for this values q_1 wil be:
So as you can see, the negative charge will always be -1.325 μC and the positive 4.17μC
Answer:
<em>The fifth option is the correct answer: mv; 2 mv</em>
Explanation:
<u>Change of Momentum</u>
Assume an object has a momentum p1 and after some interaction it now has a momentum p2, the change of momentum is
The momentum is computed as
Where m is the mass of the object and v its speed. Now let's analyze the situation of both the ball and the clay.
The clay has an initial speed v and a mass m, thus its initial momentum is
When it hits the wall, it sticks, thus its final speed is 0 and
The change of momentum is
The absolute change is mv
Now for the ball, the initial condition is the same as it was for the clay, but the ball hits back at the same speed, thus its final momentum is
The change of momentum is
The absolute change is 2mv
The fifth option is the correct answer: mv; 2 mv