[H+][OH-] = 1x10-14 = Kw (Memorize this relationship)
(2.70x10-2)[OH-] = 1x10-14
[OH-] = 1x10-14/2.70x10-2
[OH-] = 3.70x10-13 M (assuming you ignore the autoionization of H2O)
That is false (please mark me brainliest)
... in neutralization reactions, for example:
NaOH + HCl = NaCl + H₂O
2KOH + H₂SO₄ = K₂SO₄ + 2H₂O
Answer:
Option-A (XY)
Explanation:
In this problem one should focus on the number of valence electrons present in each atom. Remember that in lewis structure the dots on an atom always show the valence shell electrons. In given statement;
The,
X has one valence electron. It means that it can loose this single electron to attain the noble gas configuration i.e.
X° → X⁺ + 1e⁻
Similarly,
Y have seven valence shell electrons. Therefore, in order to complete the octet this atom will gain one electron i.e.
::Y:° + 1 e⁻ → Y⁻
Hence, we can conclude that X got stabilized by losing one electron and Y got stabilized by gaining one electron therefore, only one of each is required to form an ionic compound i.e.
<h3>
X⁺ + Y⁻ → XY</h3>
