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Pavlova-9 [17]
3 years ago
11

How many moles of carbon dioxide are produced from the complete combustion of 5.42 moles of ethanol? 2C2H6O +7 O2 ®4 CO2 + 6H2O

Chemistry
1 answer:
Evgen [1.6K]3 years ago
4 0

Answer: 10.84 moles of CO_2 will be produced from complete combustion of 5.42 moles of ethanol

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

2C_2H_6O+7O_2\rightarrow 4CO_2+6H_2O  

According to stoichiometry :

2 moles of ethanol produce =  4 moles of CO_2

Thus 5.42 moles of ethanol will produce=\frac{4}{2}\times 5.42=10.84moles  of CO_2  

Thus 10.84 moles of CO_2 will be produced from complete combustion of 5.42 moles of ethanol

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B. from 52 moles of nitric acid, how many moles of silver nitrate will be produced?
IceJOKER [234]

Answer:

39 mol AgNO3

Explanation:

We have the equation 4HNO3 + 3Ag -----> 3AgNO3 + NO + 2H2O

We want to calculate the number of silver nitrate (AgNO3) moles that would be produced from 52 moles of nitric acid ( HNO3 )

We can calculate this by using mole ratio as well as dimensional analysis.

The mole ratio of Silver nitrate to nitric acid based on the balanced equation is 3AgNO3:4HNO3.

Using this we can create a table: The table is attached.

Breakdown of the table.

The moles of nitric acid cancel out and we multiply 52 by 3/4 to get 39 moles of Silver nitrate.

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How many grams of oxygen are needed to react with 4.6 grams of titanium(IV) chloride
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Answer:

The answer to your question is 245 grams

Explanation:

Data

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mass of CaCl₂ = ?

Process

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molar mass = (1 x 40) + (2 x 35.5)

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                       111 g of CaCl₂ -------------- 1 mol

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                         x = (0.34 x 111) / 1

                         x = 37.74 g

3.- Calculate the total mass

                        37.74 g ------------------ 1 L

                            x        ------------------ 6.5 L

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Answer:

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