First, calculate for the amount of heat used up for increasing the temperature of ice.
H = mcpdT
H = (18 g)*(2.09 J/g-K)(50 K) = 1881 J
Then, solve for the heat needed to convert the phase of water.
H = (1 mol)(6.01 kJ/mol) = 6.01 kJ = 6010 J
Then, solve for the heat needed to increase again the temperature of water.
H = (18 g)(4.18 J/gK)(70 k)
H = 5266.8 J
The total value is equal to 13157.8 J
Answer: 13157.8 J
Answer:
1.88 × 10²² Molecules of CO
Explanation:
At STP for an ideal gas,
Volume = Mole × 22.4 L/mol
Or,
Mole = Volume / 22.4 L/mol
Mole = 0.7 L / 22.4 L/mol
Mole = 0.03125 moles
Now,
No. of Molecules = Moles × 6.022 × 10²³ Molecules/mol
No. of Molecules = 0.03125 × 6.022 × 10²³ Molecules/mol
No. of Molecules = 1.88 × 10²² Molecules of CO
Answer:5.4 g / 13.6 g *100
Explanation:Its is the correct answer
Answer:
the mass of 2.9 moles of calcium is 116 g
Explanation:
The computation of the mass of 2.9 moles of calcium is shown below
As we know that
Mole = mass ÷ molar mass
where,
Moles be 2.9
And, we know that the molar mass of calcium be 40g/mol
Now put the values to the above formula
2.9 = Mass ÷ 40
So, the mass would be
= 40 × 2.9
= 116 g
Hence, the mass of 2.9 moles of calcium is 116 g
Answer:
4.90 x 10 24 atoms
Explanation:
the 24 is the exponent for the 10