Answer:
ΔV=0.484mV
Explanation:
The potential difference across the end of conductor that obeys Ohms law:
ΔV=IR
Where I is current
R is resistance
The resistance of a cylindrical conductor is related to its resistivity p,Length L and cross section area A
R=(pL)/A
Given data
Length L=3.87 cm =0.0387m
Diameter d=2.11 cm =0.0211 m
Current I=165 A
Resistivity of aluminum p=2.65×10⁻⁸ ohms
So
ΔV=IR
![=I(\frac{pL}{A})\\ =I(\frac{pL}{\pi r^{2} } )\\=I(\frac{pL}{\pi (d/2)^{2} } )\\=165A((\frac{(2.65*10^{-8})(0.0387m)}{\pi (0.0211m/2)^{2} } ))\\=4.84*10^{-4}V](https://tex.z-dn.net/?f=%3DI%28%5Cfrac%7BpL%7D%7BA%7D%29%5C%5C%20%3DI%28%5Cfrac%7BpL%7D%7B%5Cpi%20r%5E%7B2%7D%20%7D%20%29%5C%5C%3DI%28%5Cfrac%7BpL%7D%7B%5Cpi%20%28d%2F2%29%5E%7B2%7D%20%7D%20%29%5C%5C%3D165A%28%28%5Cfrac%7B%282.65%2A10%5E%7B-8%7D%29%280.0387m%29%7D%7B%5Cpi%20%280.0211m%2F2%29%5E%7B2%7D%20%7D%20%29%29%5C%5C%3D4.84%2A10%5E%7B-4%7DV)
ΔV=0.484mV
The correct answer is: Option (3) 9.8 N/kg
Explanation:
According to Newton's Law of Gravitation:
--- (1)
Where G = Gravitational constant = 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²
m = Mass of the body = 2 kg
M = Mass of the Earth = 5.972 × 10²⁴ kg
R = Distance of the object from the center of the Earth = Radius of the Earth + Object's distance from the surface of the Earth = (6371 * 10³) + 3.0 = 6371003 m
Plug in the values in (1):
(1)=> ![F_g = \frac{6.67408 * 10^{-11} * 2 * 5.972*10^{24}}{(6371003)^2} = 19.63](https://tex.z-dn.net/?f=%20F_g%20%3D%20%5Cfrac%7B6.67408%20%2A%2010%5E%7B-11%7D%20%2A%202%20%2A%205.972%2A10%5E%7B24%7D%7D%7B%286371003%29%5E2%7D%20%3D%2019.63%20)
Now that we have force strength at the location, we can use:
Force = mass * gravitational-field-strength
Plug in the values:
19.63 = 2.0 * gravitational-field-strength
gravitational-field-strength = 19.63/2 = 9.82 N/kg
Hence the correct answer is Option (3) 9.8 N/kg
Work+Force*Distance. Rearranging, F=W/d. Calculating, the force must be 0.0215 N.
Answer:
B. 6 s
Explanation:
Given in the y direction:
Δy = 0 m
v₀ = 30 m/s
a = -10 m/s²
Find: t
Δy = v₀ t + ½ at²
0 m = (30 m/s) t + ½ (-10 m/s²) t²
0 = 30t − 5t²
0 = 5t (6 − t)
t = 6
Something that is definitely true is that the constant acceleration has to affect the monkey and the banana beacuse both are affected by the gravity. Gravity imparts exactly the same acceleration on both things while falling and it affects them in the same way