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2 years ago

Structural formula for 4-nonene and fluorine gas

Chemistry

2 answers:

goldenfox [79]2 years ago

6 0

I THINK it's <span>1,1-Difluorononane, or </span> $C_9H_{18}F_2$ .<span>
</span>

Savatey [412]2 years ago

6 0

I'm not sure how to draw it and show you, but I will type it out and hopefully you will understand.

4-nonene means the double bond is the fourth possible one:
CH 3 - CH 2 - CH 2 - CH=CH-CH 2 - CH 2 - CH 2 - CH 3
adding F2 means F2 are added across the double bond
-> CH 3 - CH 2 - CH 2 - CHF-CHF-CHF- CH 2 - CH 2 - CH 2 - CH 3
So: C9H18+F2 --> C9H18F2

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Which of the following statements correctly describe(s) the driving forces for diffusion of Na+ and K+ ions through their respec

melomori [17]

Question:

Which of the following statements correctly describe(s) the driving forces for diffusion of Na+ and K+ ions through their respective channels? Select all that apply.

A)The diffusion of Na+ ions into the cell is facilitated by the Na+ concentration gradient across the plasma membrane.

B)The diffusion of Na+ ions into the cell is impeded by the electrical gradient across the plasma membrane.

C)The diffusion of K+ ions out of the cell is impeded by the K+ concentration gradient across the plasma membrane.

D)The diffusion of K+ ions out of the cell is impeded by the electrical gradient across the plasma membrane. The electrochemical gradient is larger for Na+ than for K+.

Answer:

"The concentration gradient and the electro-chemical gradient" describes the driving forces for diffusion of Na+ and K+ ions through their respective channels

Explanation:

The Na ions diffusion inside the cell is facilitated by the concentration gradient of the Na ions which is present across the plasma membrane. Hence, the diffusion of the K ions which is present outside the cell and will be impeded due to the electrical gradient which is present near the plasma membrane. Thus, the electro-chemical gradient is greater as compared to the Na ion than that of the K ion.

6 0

3 years ago

Is chlorine a substance or a mixture

WARRIOR [948]

Answer:

its a substance

Explanation:

8 0

2 years ago

Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample

goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=2:2=1:1$

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=3:3=1:1$

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.

4 0

3 years ago

Please help ill give brainliest

boyakko [2]

Answer: The answer to the first one is the second option and the answer for the second one is the first option.

Explanation:

5 0

2 years ago

Read 2 more answers

15.50 g of NH4Cl reacts with an excess of AgNO3. In the reaction 35.50 g AgCl is produced. what is the theoretical yield of AgCl

Readme [11.4K]

Answer:

The answer to your question is 41.6 g of AgCl

Explanation:

Data

mass of NH₄Cl = 15.5 g

mass of AgNO₃ = excess

mass of AgCl = 35.5 g

theoretical yield = ?

Process

1.- Write the balanced chemical reaction.

NH₄Cl + AgNO₃ ⇒ AgCl + NH₄NO₃

2.- Calculate the molar mass of NH₄Cl and AgCl

NH₄Cl = 14 + 4 + 35.5 = 53.5 g

AgCl = 108 + 35.5 = 143.5 g

3.- Calculate the theoretical yield

53.5 g of NH₄Cl -------------------- 143.5 g of AgCl

15.5 g of NH₄Cl ------------------- x

x = (15.5 x 143.5) / 53.5

x = 2224.25 / 53.5

x = 41.6 g of AgCl

8 0

3 years ago