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4vir4ik [10]
3 years ago
12

Structural formula for 4-nonene and fluorine gas

Chemistry
2 answers:
goldenfox [79]3 years ago
6 0
I THINK it's <span>1,1-Difluorononane, or </span>C_9H_{18}F_2.<span>
</span>

Savatey [412]3 years ago
6 0
I'm not sure how to draw it and show you, but I will type it out and hopefully you will understand. 

 4-nonene means the double bond is the fourth possible one:
CH 3 - CH 2 - CH 2 - CH=CH-CH 2 - CH 2 - CH 2 - CH 3
adding F2 means F2 are added across the double bond
-> CH 3 - CH 2 - CH 2 - CHF-CHF-CHF- CH 2 - CH 2 - CH 2 - CH 3
So: C9H18+F2 --> C9H18F2
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erastova [34]

Answer : The grams of carbon monoxide needed are 148.89 g

Solution : Given,

Mass of iron, Fe = 198.5 g

Molar mass of iron, Fe = 56 g/mole

Molar mass of carbon monoxide, CO = 28 g/mole

First we have to calculate the moles of iron, Fe.

\text{ Moles of Fe}=\frac{\text{ Mass of Fe}}{\text{ Molar mass of Fe}}=\frac{198.5g}{56g/mole}=3.545moles

The balanced chemical reaction is,

Fe_2O_3(s)+3CO(g)\rightarrow 3CO_2(g)+2Fe(s)

From the balanced reaction, we conclude that

2 moles of iron produces from the 3 moles of carbon monoxide

3.545 moles of iron produces from the \frac{3}{2}\times 3.545=5.3175 moles of carbon monoxide

Now we have to calculate the mass of carbon monoxide, CO.

\text{ Mass of CO}=\text{ Moles of CO}\times \text{ Molar mass of CO}

\text{ Mass of CO}=(5.3175moles)\times (28g/mole)=148.89g

Therefore, the grams of carbon monoxide needed are 148.89 g

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3 years ago
If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
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