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Kobotan [32]
4 years ago
14

In short-track speed skating, the track has straight sections and semicircles 16 m m/s .Part A What is the horizontal force on t

he skater? part B What is the ratio of this force to the skater's weight?kg skater goes around the turn at a constant 11m/s m in diameter. Assume that a 64kg
Physics
1 answer:
igomit [66]4 years ago
6 0

Answer:

(a) F=968N

(b) Ratio=1.542

Explanation:

Given data

Diameter d=16m

Radius r=d/2=16/2=8.0m

Mass m=64kg

Speed v=11m/s

For Part (a)

From Newtons second law we have:

F=ma\\as\\a=v^{2}/r\\ so\\F=m\frac{v^{2}}{r}\\ F=64kg\frac{(11m/s)^2}{8m}\\ F=968N

For Part (b)

The weight is calculated as:

w=mg\\w=(64kg)(9.81m/s^2)\\w=627.84N

Therefore we have the ratio of centripetal force to the weight is given as:

Ratio=F/w\\Ratio=968N/627.84\\Ratio=1.542

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The moment of inertia of a thin ring of mass M and radius R about its symmetry axis is ICM = MR2.
monitta

Answer:

The moment of inertia of large ring is 2MR².

(A) is correct option.

Explanation:

Given that,

Mass of ring = M

Radius of ring = R

Moment of inertia of a thin ring = MR²

Moment of inertia :

Moment of inertia is the product of the mass of the ring and square of radius of the ring.

We need to calculate the moment of inertia of large ring

Using formula of moment of inertia

I=I_{cm}+MR^2

Where, I_{cm} = moment of inertia at center of mass

M = mass of ring

R = radius of ring

Put the value into the formula

I=MR^2+MR^2

I=2MR^2

Hence, The moment of inertia of large ring is 2MR².

6 0
3 years ago
Which component of physical fitness is skill related a) flexibility, b) cardio respiratory endurance, c) muscular strength, d) a
WARRIOR [948]

Answer:

d) Agility

Explanation:

Agility is defined as the capability or ability of the body to change the position of the body efficiently, and it requires the isolated movement's integration skills by using a combination of speed, balance, reflexes, coordination, strength, and endurance.

In the field of sport, it is categorized in a unique sport because it is a combination of various factors.

Therefore, agility is a component that is related to skill-related physical fitness.

8 0
3 years ago
A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied
Vika [28.1K]

We have that for the Question "A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that  the minimum force that must be applied on the <em>book is</em>

  • F=44N

From the question we are told

A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal

Generally the equation for the  Force  is mathematically given as

F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\

F=44N

Therefore

the minimum force that must be applied on the <em>book is</em>

F=44N

For more information on this visit

brainly.com/question/23379286

8 0
3 years ago
While standing on ice, you first throw a tennis ball and then a bowling ball. Which one would cause you to have the greatest neg
marshall27 [118]
<span>Throwing the bowling ball would have the greatest negative velocity becasue Principle of the Conservation of Momentum states that: if objects collide, the total momentum before the collision is the same as the total momentum after the collision (provided that no external forces - for example, friction - act on the system). That’s amazingly useful because it means that you can tell what is going to happen after a collision before it has taken place. Principle of Conservation of Energy: Of course, energy is also conserved in any collision, but it isn't always conserved in the form of kinetic energy.</span>
3 0
3 years ago
Read 2 more answers
How much work w is done by the electrostatic force on the moving point charge?
V125BC [204]

As we know that electrostatic force is a conservative force

so we can say by the condition of conservative force

F_c = -\frac{dU}{dr}

here we can rearrange the above equation as

dU = - F_c.dr

now integrate both sides

\int dU = - \int F_c . dr

Now we know by the definition of work done by a force is given by

W = \int F.dr

now work done by conservative force is given as

W_c = \int F_c . dr

Now from above work done by electric field to move charge from one point to other is given as

W_{EF} = \int F_{e}.dr = - \int dU

so here work done is given as

W_{EF} = U_i - U_f

so change in potential energy is given by work done

3 0
4 years ago
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