Answer:
a. 0,035M
Explanation:
For the reaction:
Ba(OH)₂(s) ⇄ Ba²⁺(aq) + 2OH⁻(aq)
Ksp is defined as:
Ksp = [Ba²⁺] [OH⁻]²
5x10⁻³ = [Ba²⁺] [OH⁻]²
if is added a solution of 1M of Ba²⁺:
5x10⁻³ = [1M] [OH⁻]²
The addition of barium hydroxide Ba(OH)₂ gives:
[Ba²⁺] = 1M + x
[OH⁻]² = 2x
Replacing:
5x10⁻³ = [1 + x] [2x]²
5x10⁻³ = 4x² + 4x³
Solutions are:
x = -1,00 M
x = -0,036 M
<em><u>x = 0,035 M</u></em> → Right answer, there are not negative concentrations.
Thus, solubility is
<em>a. 0,035M</em>
<em></em>
I hope it helps!
Answer:
Lanthanides and Actinides
Explanation:
Answer:
The mass percentage of carbon can be found easily using the molar mass of C6H12O6, 180.1559 g/mol. We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass. C6H12O6 = CO2 + C3H6O3 + CH3OCH3 Take fructose for example. Compound.
Explanation: I looked it up
Answer:
4,38%
small molecular volumes
Decrease
Explanation:
The percent difference between the ideal and real gas is:
(47,8atm - 45,7 atm) / 47,8 atm × 100 = 4,39% ≈ <em>4,38%</em>
This difference is considered significant, and is best explained because argon atoms have relatively <em>small molecular volumes. </em>That produce an increasing in intermolecular forces deviating the system of ideal gas behavior.
Therefore, an increasing in volume will produce an ideal gas behavior. Thus:
If the volume of the container were increased to 2.00 L, you would expect the percent difference between the ideal and real gas to <em>decrease</em>
<em />
I hope it helps!