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3 years ago

5

What is the coldest part of the cat’s body?

1 answer:

Nina [5.8K]3 years ago

3 0

Answer:

It Depends Cat is indoor or outdoor But As per the body part concern that i will Considered around the neck but Temperature Remain the same which i Analyzed too

Explanation:

A cat's normal body temperature can range from 100.5 to 102.5 degrees. Because 101.5 degrees is right in the middle, it's often referred to as a “normal” body temperature. Being that their body temperature is higher than ours, they can also tolerate higher temperatures (provided they have access to water).

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A long, rigid conductor, lying along an x axis, carries a current of 4.99 A in the negative x direction. A magnetic field is pre

Tcecarenko [31]

Answer with Explanation:

We are given that

Current in conductor=I=4.99 A (-x direction)

Magnetic field=B= $3.72\hat{i}+8.72x^2\hat{j}mT=(3.72i+8.72x^2j)\times 10^{-3}$

(1mT= $10^{-3} T$ )

x(in m) and B (in mT)

Length of conductor is given in negative x- direction

$\vec{L}=-x\hat{i}$

$dL=-dx\hat{i}$

Force on current carrying conductor is given by

$F=I(L\times B)$

$dF=I(dL\times B)$

Integrating on both sides then we get

$\vec{F}=\int_{1.41}^{2.77}(4.99)(-dx\hat{i}\times (3.72\hat{i}+8.72x^2\hat{j}))\times 10^{-3}$

$\vec{F}=-\int_{1.41}^{2.77}(4.99\times 10^{-3})\cdot 8.72(x^2\hat{k})dx$ ( $i\times i=0, i\times j=k$

$\vec{F}=-(4.99\times 10^{-3}\times 8.72)[\frac{x^3\hat{k}}{3}]^{2.77}_{1.41}$

$\vec{F}=-\frac{(4.99\times 10^{-3}\cdot 8.72)}{3}((2.77)^3-(1.41)^3)\hat{k}$

$\vec{F}=-0.268 \hat{k} N$

a. x- component of force=0

b.y- component of force=0

c.z- component of force=-0.268 N

5 0

3 years ago

1) what is a calorie?<br>

Bogdan [553]

I read it’s a unit of energy

3 0

3 years ago

Complete the sentence to explain when waves interact.

rewona [7]

Answer:

Objects and waves

Explanation:

7 0

3 years ago

During a particular thunderstorm, the electric potential difference between a cloud and the ground is Vcloud - Vground = 4.20 10

Mazyrski [523]

Answer:

The electric potential energy is 6.72 x 10^-11 J.

Explanation:

Potential difference, V = 4.2 x 10^8 V

charge of electron, q = - 1.6 x 10^-19 C

Let the potential energy is U.

U = q V

U = 1.6 x 10^-19 x 4.2 x 10^8

U = 6.72 x 10^-11 J

6 0

3 years ago

Which change will increase the speed of a sound wave traveling in a solid aluminum rod? changing the rod from a solid to a liqui

Pepsi [2]

Answer:

increasing the temperature of the rod

Explanation:

Sound wave is a longitudinal wave and its speed in a solid rod is given by the formula

$v = \sqrt{\frac{Y}{\rho}}$

here we know that

Y = young's modulus

$\rho$ = density of the medium

so as we increase the temperature of rod the density of the rod will decrease while the elasticity will remain same

So on increasing the temperature we can say that speed will increase due to decrease in the density

4 0

3 years ago