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BARSIC [14]
3 years ago
13

Which change will increase the speed of a sound wave traveling in a solid aluminum rod? changing the rod from a solid to a liqui

d changing the rod from a solid to a gas decreasing the temperature of the rod increasing the temperature of the rod
Physics
1 answer:
Pepsi [2]3 years ago
4 0

Answer:

increasing the temperature of the rod

Explanation:

Sound wave is a longitudinal wave and its speed in a solid rod is given by the formula

v = \sqrt{\frac{Y}{\rho}}

here we know that

Y = young's modulus

\rho = density of the medium

so as we increase the temperature of rod the density of the rod will decrease while the elasticity will remain same

So on increasing the temperature we can say that speed will increase due to decrease in the density

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A 10.0 L tank contains 0.329 kg of helium at 28.0 ∘C. The molar mass of helium is 4.00 g/mol . Part A How many moles of helium a
nadya68 [22]

Answer:

82.25 moles of He

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 10 L

Mass of He = 0.329 Kg

Temperature (T) = 28.0 °C

Molar mass of He = 4 g/mol

Mole of He =?

Next, we shall convert 0.329 Kg of He to g. This can be obtained as follow:

1 Kg = 1000 g

Therefore,

0.329 Kg = 0.329 Kg × 1000 g / 1 Kg

0.329 Kg = 329 g

Thus, 0.329 Kg is equivalent to 329 g.

Finally, we shall determine the number of mole of He in the tank. This can be obtained as illustrated below:

Mass of He = 329 g

Molar mass of He = 4 g/mol

Mole of He =?

Mole = mass / molar mass

Mole of He = 329 / 4

Mole of He = 82.25 moles

Therefore, there are 82.25 moles of He in the tank.

8 0
3 years ago
What is the correct definition of nurture?
makkiz [27]

Answer:

(C) the fulfillment of physical, mental, emotional, and social needs

Explanation:

Nurture

Definition (A) - <u><em>Care for and encourage the growth or development of</em></u>

Definition (B) - <u><em>The process of caring for and encouraging the growth or development of someone or something</em></u>

The best definition in the answer list for the word "nurture" is answer (C) The fulfillment of physical, mental, emotional, and social needs

8 0
3 years ago
Read 2 more answers
If the primary of a transformer were connected to a dc power source,
QveST [7]

Answer:

D. only briefly while being connected or disconnected.

Explanation:

As we know that transformer works on the principle of mutual inductance

here we know that as per the principle of mutual inductance when flux linked with the primary coil charges then it will induce EMF in secondary coil

So here when AC source is connected with primary coil then it will give output across secondary coil because AC source will have change in flux with time.

Now when we connect DC source across primary coil then it will not induce any EMF across secondary coil because DC source is a constant voltage source in which flux will remain constant always

So here in DC source the EMF will only induce at the time of connection or disconnection when flux will change in it while rest of the time it will give ZERO output

so correct answer will be

D. only briefly while being connected or disconnected.

8 0
3 years ago
According to the law of conservation of matter,the number of ______ is not changed by a chemical reaction
abruzzese [7]
The answer is mass. I have to comment more than 20 characters.
6 0
3 years ago
Read 2 more answers
How can a 1kg ball have more kinetic energy than a 100kg ball? Explain both using words and by providing a numerical example
MariettaO [177]

1 kg ball can have more kinetic energy than a 100 kg ball as increase in velocity is having greater impact on K.E than increase in mass.

<u>Explanation</u>:

We know kinetic energy can be judged or calculated by two parameters only which is mass and velocity. As kinetic energy is directly proportional to the (velocity)^2 and increase in velocity leads to greater effect on translational Kinetic Energy. Here formula of Kinetic Energy suggests that doubling the mass will double its K.E but doubling velocity will quadruple its velocity:

\text { Kinetic Energy }=\frac{1}{2} m v^{2}

Better understood from numerical example as given:

If a man A having weight 50 kg run with speed 5 m/s and another man B having 100 kg weight run with 2.5 m / s. Which man will have more K.E?

This can be solved as follows:

\text { Kinetic Energy of } \mathrm{A}=\frac{1}{2} 50 \times 5^{2}=625 \mathrm{J}

\text { Kinetic Energy bf } \mathrm{B}=\frac{1}{2} 100 \times 2.5^{2}=312.5 \mathrm{J}

It shows that man A will have more K.E.

Hence 1 kg ball can have more K.E than 100 kg ball by doubling velocity.

4 0
3 years ago
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