The two blocks of masses M and 2M shown above initially travel at the same speed v but in opposite directions. They collide and
1 answer:
Answer:
option B.
Explanation:
given,
Mass of the blocks 1 = M
Mass of the blocks 1 = 2 M.
initial speed of the block 1= v
initial speed of the block 2 = - v
where V is the final speed of the blocks after collision
using conservation of momentum
M v + 2 M (-v) = (M + 2 M) V
3 M V = - M v
velocity of the blocks after collision is equal to -v/3 m/s
hence, the correct answer is option B.
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Complete question:
At a particular instant, an electron is located at point (P) in a region of space with a uniform magnetic field that is directed vertically and has a magnitude of 3.47 mT. The electron's velocity at that instant is purely horizontal with a magnitude of 2×10⁵ m/s then how long will it take for the particle to pass through point (P) again? Give your answer in nanoseconds.
[<em>Assume that this experiment takes place in deep space so that the effect of gravity is negligible.</em>]
Answer:
The time it will take the particle to pass through point (P) again is 1.639 ns.
Explanation:
F = qvB
Also;
solving this two equations together;
where;
m is the mass of electron = 9.11 x 10⁻³¹ kg
q is the charge of electron = 1.602 x 10⁻¹⁹ C
B is the strength of the magnetic field = 3.47 x 10⁻³ T
substitute these values and solve for t
Therefore, the time it will take the particle to pass through point (P) again is 1.639 ns.
12.8 rad
Explanation:
The angular displacement through which the wheel turned can be determined from the equation below:
(1)
where
Using these values, we can solve for from Eqn(1) as follows:
or