The two blocks of masses M and 2M shown above initially travel at the same speed v but in opposite directions. They collide and
1 answer:
Answer:
option B.
Explanation:
given,
Mass of the blocks 1 = M
Mass of the blocks 1 = 2 M.
initial speed of the block 1= v
initial speed of the block 2 = - v
where V is the final speed of the blocks after collision
using conservation of momentum
M v + 2 M (-v) = (M + 2 M) V
3 M V = - M v
velocity of the blocks after collision is equal to -v/3 m/s
hence, the correct answer is option B.
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Answer:
true b and c
Explanation:
n the electromechanical transitions of the atoms the relationship must be fulfilled
= R (1 / nf - 1 / no²)
where for the final state nf = 1 giving in the case of hydrogen the Lymma series whose smallest wavelength is lam = 122 nm with nf = 1 and there are a series of spectral lines for each value of n of the final state
in the case of sodium so well it has a transition from an excited state to the kiss state (bad)
Now let's review the different proposals
a) False. The electronic potential for sodium is much lower than for hydrognosia
b) True
c) True
d) true