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Dmitry [639]
3 years ago
8

Two ships leave a harbor at the same time, traveling on courses that have an angle of 110∘ between them. If the first ship trave

ls at 22 miles per hour and the second ship travels at 34 miles per hour, how far apart are the two ships after 1.2 hours?

Physics
1 answer:
Allushta [10]3 years ago
6 0

Answer:

49.07 miles

Explanation:

Angle between two ships = 110° = θ

First ship speed = 22 mph

Second ship speed = 34 mph

Distance covered by first ship after 1.2 hours = 22×1.2 = 26.4 miles = b

Distance covered by second ship after 1.2 hours = 34×1.2 = 40.8 miles = c

Here the angle between the two sides of a triangle is 110° so from the law of cosines we get

a² = b²+c²-2bc cosθ

⇒a² = 26.4²+40.8²-2×26.4×40.8 cos110

⇒a² = 2408.4

⇒a = 49.07 miles

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Explanation:

Given that :

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Tt = Ts + Ce^-kt

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Equation becomes :

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t when Tt = 160

160 = 70 + 135e^-0.031k

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Explanation:

The frequency of the wave is defined as the number of cycles per second of the wave:

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Frequency is measured in Hertz (Hz).

In this problems, the wave has

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