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Alex787 [66]
3 years ago
5

What is the relationship between photosynthesis and cellular respiration in plants? YOU WILL GWT 18 POINTS!!!!!!!!

Chemistry
2 answers:
Neko [114]3 years ago
7 0
Photosynthesis converts carbon dioxide and water into oxygen and glucose. Glucose is used as food by the plant and oxygen is a by-product. Cellular respiration converts oxygen and glucose into water and carbon dioxide. Water and carbon dioxide are by- products and ATP is energy that is transformed from the process.
Goshia [24]3 years ago
7 0
It’s 9 points and I’m sorry I HAVE NO IDEA AT ALLLLLLLLL
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A sample of gold (Au) has a mass of 35.12 g..
VMariaS [17]
A) Molar mass gold ( Au) = 196.96 g/mol

1 mole Au ----------- 196.96 g
? moles Au ---------- 35.12 g

35.12 x 1 / 196.96

= 0.178 moles of Au
_____________________________

b) 196.96 g --------------- 6.02x10²³ atoms
    35.12 g ---------------- ( atoms ? )

35.12 x ( 6.02x10²³) / 196.96

2.114x10²⁵ / 196.96

= 1.07x10²³ atoms
_____________________________________________

7 0
3 years ago
Read 2 more answers
how would the rate of diffusion change if the po2 in the capillaries was 40 mmhg and the po2 in the muscle cell changed from 40
BlackZzzverrR [31]

The rate of diffusion change would increase if the PO₂ in the capillaries was 40 mmHg and the PO₂ in the muscle cell changed from 40 to 20 mmHg.

Simple diffusion is the movement of molecular substances from a region of higher concentration to lower concentration. The mechanism with which the movement of O₂ travels from the blood to the body tissues takes place with the use of simple diffusion.

Now, if PO₂ changes from 40 → 20 mmHg in the muscle cells, and the PO₂ in the blood = 40mmHg. It implies that the pressure gradient(P) has increased. As such, there is an increase in the rate of diffusion of oxygen from the blood to muscle cells.

Learn more about diffusion here:

brainly.com/question/14392880?referrer=searchResults

6 0
2 years ago
PLEASE HELP!!
lana66690 [7]

Answer:

c

Explanation:

3 0
3 years ago
Read 2 more answers
An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is
Juli2301 [7.4K]

Answer:

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}  

Explanation:

The gas ideal law is  

PV= nRT (equation 1)

Where:

P = pressure  

R = gas constant  

T = temperature  

n= moles of substance  

V = volume  

Working with equation 1 we can get  

n =\frac{PV}{RT}

The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.

\frac{m}{mw} =\frac{PV}{RT}  or  

m =\frac{P*V*mw}{R*T}   (equation 2)

The cylindrical container has a constant pressure p  

The volume is the volume of a cylinder this is

V =(pi)*r^{2}*h

Where:

r = radius  

h = height  

(pi) = number pi (3.1415)

This cylinder has a radius, r and height, h so the volume is  V =(pi)*r^{2}*h

Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:  

T =\frac{T_{1} + T_{O}}{2}  

Replacing these values in the equation 2 we get:

m =\frac{P*V*mw}{R*T}   (equation 2)

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}    

8 0
4 years ago
What is the pH of a solution with [H-] = 4.3 x 10-4 M?
Temka [501]

Answer:

3.37

Explanation:

pH=-log(H3O+)

- Hope that helps! Please let me know if you need further explanation.

4 0
4 years ago
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