Which element is most likely to form an ion with a negative 2 charge?

Rills, gullies, streams, rivers and tributaries are all caused by

baherus [9]

Answer:

Explanation:All these bodies of water are formed when water flows from the top, such as from a hill, mountain, or down a valley, etc. In these high areas, melting snow causes tiny streams of water to flow down. They are also formed when small bodies of water combine to form larger bodies. For instance, A stream is a channel along which water is continually flowing down a slope. Unlike gullies, streams rarely dry up. Small streams are also called creeks or brooks. As streams flow together, they form larger and larger bodies of flowing water. A large stream is often called a river

5 0

4 years ago

Light strikes a metal surface, causing photoelectric emission. The stopping potential for the ejected electrons is 7.9 V, and th

earnstyle [38]

Answer:

The wavelength of light is $1.11\times 10^{-7}\ m$ .

Explanation:

Given:

Work function of the metal (Ф) = 3.3 eV = $3.3\times 1.6\times 10^{-19}\ J=5.28\times 10^{-19}\ J$

Stopping potential (V) = 7.9 V

Wavelength of light (λ) = ?

We know that for photoelectric effect to take place, the minimum energy of the incident photon must be equal to the sum of maximum kinetic energy and the work function of the metal surface. This means,

$E_p=K_{max}+\phi$

Now, the kinetic energy of the electrons emitted must be at least equal to the product of stopping potential and the charge on electron of the metal in order to escape the metal surface. Therefore,

$K_{max}=eV$

Where, 'e' is the charge on one electron = $1.6\times 10^{-19}\ C$

Also, the energy of photon is expressed as:

$E_p=\frac{hc}{\lambda}\\\\Where,\\h\to\ Planck's\ constant=6.626\times 10^{-34}\ Js\\c\to\ velocity\ of\ light=3\times 10^{8}\ m/s$

Now, the above equation becomes,

$\frac{hc}{\lambda}=eV+\phi\\\\\lambda=\frac{hc}{eV+\phi}$

Plug in all the given values and solve for λ. This gives,

$\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^{8}}{1.6\times10^{-19}\times 7.9+5.28\times 10^{-19}}\\\\\lambda=1.11\times 10^{-7}\ m$

Therefore, the wavelength of light is $1.11\times 10^{-7}\ m$ .

4 0

4 years ago

HELP!

Angelina_Jolie [31]

Answer:

speed is increasing.

this is because the graph has a positive slope (due to it going up ), if it were decreasing, the graph would be going down

4 0

3 years ago

Read 2 more answers

Un automovil parte del reposo y acelera uniformemente hasta alcanzar una rapidez de 0,255km/h en un tiempo de 3/4 Minutos determ

Elden [556K]

Answer:

a = 1.5*10^-3 m/s^2

x = 0.033m = 3.3cm

Explanation:

To calculate the acceleration and the distance traveled by the car you use the following formulas:

$v=v_o+at$ (1)

$x=v_ot+\frac{1}{2}at^2$ (2)

v: final velocity = 0,255 km/h

vo: initial velocity = 0 m/s

t: time = 3/4 min

a: acceleration = ?

x: distance

In order to use the equations (1) and (2) you first convert the units of the final velocity to m/s, and the time to seconds.

$v=0,255\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}\\\\v=0.07m/s\\\\t=\frac{3}{4}min*\frac{60s}{1min}=45s$

Next, you solve the equation (1) for the acceleration a:

$a=\frac{v}{t}=\frac{0.07m/s}{45s}=1.5*10^{-3}\frac{m}{s^2}$

With this value of a you can calculate the distance traveled by the car, by using the equation (2):

$x=\frac{1}{2}(1.5*10^{-3}m/s^2)(45s)^2=0.033m=3.3cm$

hence, the acceleration of the car is 1.5*10^-3 m/s^2 and the distance traveled in 3/4 min is 0.033m

5 0

4 years ago

Identify which objects will accelerate to the left, which will accelerate to the right,and those that will not accelerate. Optio

Licemer1 [7]

Answer:

The situation given in option A and B are examples for moving an object toward left side while the option C and option D are examples for moving an object toward right side. Option B will also be an example for not moving the object.

Explanation:

As per the option A statement, the force acting towards left is greater than the force acting toward right side. So the net force will be towards the direction having maximum magnitude. Thus, the box will move toward left side in option A. The same situation arises for the object in option B. But here the difference in the forces is only 1 N, so the change in the position of the object will be very less. Thus it may look like there is no acceleration in the box of option B.

Similarly, the force acting on the objects given in option C and D have magnitude greater towards the right side than towards the left side. So these two will be accelerated toward the right side.

3 0

4 years ago