Which element is most likely to form an ion with a negative 2 charge?

An aluminum calorimeter with a mass of 100 g contains 250 g of water. The calorimeter and water are in thermal equilibrium at 10

Nadya [2.5K]

Answer:

1822.14 J/kg C

Explanation:

Mass of aluminum = 0.100 kg

Mass of Water = 0.250 kg

Mass of copper = 0.300 kg

Mass of unknown object = 0.70 kg

Initial temperature of Aluminum = 10 C

Initial temperature of water = 10 C

Initial temperature of copper = 30 C

Initial temperature of = 100 C

Final temperature of all substances = 20 C

Change in temperature of each of them Aluminum, water , copper and unknown material respectively = 10 C , 10 C , -10 C, -80 C respectively

Specific heat of each of them Aluminum, water , copper and unknown material respectively = 900,4186,387 and c respectively.

Heat gained by aluminum and water = (0.1)(900)(10) + (0.250)(4186)(10) = 11365 j

heat lost by copper and unknown material =(0.3)(387)(-10) = -1161

heat lost by unknown material = (0.070)(c)(-80) = -5.6 c

Now solve for c using the calorimetry principle.

Heat lost + Heat gained = 0

⇒ -5.6 c = -11365 - (-1161) = -10204 j

Specific heat of unknown material = - 10204 / -5.6

= 1822.14 j/kg C

b) Material having a specific heat of 1800 j /kg C is

Polyurethane elastomer.

4 0

3 years ago

A titanium bicycle frame displaces 0.314 l of water and has a mass of 1.41 kg.part what is the density of the titanium in g/cm3

nlexa [21]

Answer;

= 4.49 g/cm³

Explanation;

Density = Mass / Volume

mass = 1.41 kg,

volume = 0.314 L

but; 1 kg = 1000 g and 1 L = 1000 mL

Thus;

Density = 1.41 kg/0.314L

Density = 4.49 kg/L (1000g/ 1kg)(1L/1000cm^3)

Density = 4.49 g/cm^3

4 0

3 years ago

A block of mass M1 = 288.0 kg sits on an inclined plane and is connected to a bucket with a massless string over a massless and

AlekseyPX

Answer:

M2 = 278.06 kg

Explanation:

We calculate the weight of M1

W=m*g

Where

m: mass (kg)

g: acceleration due to gravity (m/s²)

W₁=288* 9.8= 2822.4 N

Look at the attached graphic

We calculate the x-y components of the weight :

W₁x= 2822.4*sin41° N =1851.66 N

W₁y= 2822.4 *cos41° N = 2130.09 N

We apply Newton's first law for the balance in M1:

Σ Fy=0

Fn-W₁y=0 , Fn: normal force

Fn=W₁y=2130.09N

Friction Force = Ff=μs *Fn = 0.41*2130.09 =873.34 N

Σ Fx=0

T- W₁x- Ff=0

T= 1851.66 + 873.34

T=2725 N

We apply Newton's first law for the balance in M2:

Σ Fy=0

T- W₂ =0

W₂ = T = 2725 N

W₂ = M2*g

M2 = W₂/g

M2 = 2725/9.8

M2 = 278.06 kg

6 0

3 years ago

If Earth orbited the Sun in 9 months instead of 12, then, compared with a sidereal day, a solar day would be

Tcecarenko [31]

Answer:

longer

Explanation:

The relationship between the solar day and sidereal is as follows:

The length of the sidereal day is

= (Solar day) (solar year ÷ solar year + 1 day)

As it can be seen that the day i.e. solar its length would be greater as compared with the sidereal day.

In the case when the earn orbited the sun in 9 months rather than 12 so here the sidereal day would be the similar but the solar day would be longer as compared with the original one

7 0

3 years ago

Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are

dolphi86 [110]

Answer:

a) P1+P2

Explanation:

The magnitude of their combined momentum is just the addition of each momentum, because in this case of inelastic collision, the kinetic energy of the two cars are both converted to some form of energy because the velocity of both cars becomes zero, i.e., V=0, making P = mv = 0, this means the magnitude of P1 + P2 = 0.

3 0

3 years ago