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xz_007 [3.2K]
3 years ago
8

For each of the following scenarios, describe the force providing the centripetal force for the motion: (Be very specific, and g

ive some reasoning to your answer.) a. a car making a turn b. a child swinging around a pole c. a person sitting on a bench facing the center of a carousel d. a rock swinging on a string e. the Earth orbiting the Sun.
Physics
1 answer:
Leviafan [203]3 years ago
7 0

Answer:

a) tires rubbing, b) the weight has a component parallel to the floor

c) he child's back support, d)  The tension of the rope and weight

Explanation:

In this exercise, we are asked to indicate the origin of the forces for the centripetal movement  parallel to the rope,  e) gravitational force

a) When a car turns, the centripetal force has two origins

* The tires rubbing against the road

* If the road has a lean angle, the component of the weight directed towards the center of the circle also contributes to the centripetal force.

b) the child in general has some degree of inclination with respect to the post, for which the weight has a component parallel to the floor that is responsible for the centripetal movement of the system

c) The bench rotates together with the carousel, so the child's back support is the response to the centripetal force

d) The tension of the rope has two components: the component perpendicular to the movement and the component of the weight (parallel to the rope) the difference of these two forces is the centripetal force

e) The gravitational force of the sun on the earth is what creates the centripetal motion

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Given that,

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Let v1, , vk be vectors, and suppose that a point mass of m1, , mk is located at the tip of each vector. The center of mass for
g100num [7]

Answer:

Explanation:

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Xcm = (Σmi•xi) / M

Where i= 1,2,3,4.....

M = m1+m2+m3 +....

x is the position of the mass (x, y)

Now,

Given that,

u1 = (−1, 0, 2) (mass 3 kg),

m1 = 3kg and it position x1 = (-1,0,2)

u2 = (2, 1, −3) (mass 1 kg),

m2 = 1kg and it position x2 = (2,1,-3)

u3 = (0, 4, 3) (mass 2 kg),

m3 = 2kg and it position x3 = (0,4,3)

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Now, applying center of mass formula

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Xcm = (m1•x1+m2•x2+m3•x3+m4•x4) / (m1+m2+m3+m4)

Xcm = [3(-1, 0, 2) +1(2, 1, -3)+2(0, 4, 3)+ 5(5, 2, 0)]/(3 + 1 + 2 + 5)

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Xcm = (24, 19, 9) / 11

Xcm = (2.2, 1.7, 0.8) m

This is the required center of mass

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3 years ago
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