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REY [17]
3 years ago
7

5. Which type of energy resource is hamessed beneath the Earth's surface? A. biomass B.solar C.hydroelectric D.geothermal

Physics
1 answer:
Elan Coil [88]3 years ago
5 0

<u><em>It's called geothermal energy, and is present due to the incredible amount of heat present in Earth's interior from radioactive decay, friction, and residual heat from Earth's formation.</em></u>

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Assuming things about someone based on your experiences with similar people you have encountered is called
AysviL [449]

Answer:

presumptuous

Explanation:

it's what you call someone who assumes something

3 0
3 years ago
Future space rockets might propel themselves by firing laser beams, rather than exhaust gases, out the back. The acceleration wo
Nina [5.8K]

Answer:

Acceleration = 0.0282 m/s^2

Distance = 13.98 * 10^12 m

Explanation:

we will apply the energy theorem

work done = ΔK.E ( change in Kinetic energy )  ---- ( 1 )

<em>where :</em>

work done = p * t

                  = 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J

( note : convert 1 year to seconds )

and ΔK.E = 1/2 mVf^2   given ; m = 1200 kg  and initial V = 0

<u>back to equation 1 </u>

473040000 * 10^6  = 1/2 mv^2

Vf^2 = 2(473040000 * 10^6 ) / 1200

∴ Vf = 887918.92 m/s

<u>i) Determine how fast the rocket is ( acceleration of the rocket )</u>

a = Vf / t

  = 887918.92 / ( 1 year )

  = 0.0282 m/s^2

<u>ii) determine distance travelled by rocket </u>

Vf^2 - Vi^2 = 2as

Vi = 0

hence ; Vf^2 = 2as

s ( distance ) =  Vf^2 / ( 2a )

                     = ( 887918.92 )^2 / ( 2 * 0.0282 )

                    = 13.98 * 10^12 m

8 0
3 years ago
Help with these three
Elenna [48]
The first: alright, first: you draw the person in the elevator, then draw a red arrow, pointing downwards, beginning from his center of mass. This arrow is representing the gravitational force, Fg.
You can always calculate this right away, if you know his mass, by multiplying his weight in kg by the gravitational constant
g = 9.81 \frac{m}{s {}^{2} }
let's do it for this case:
f_{g}  = m \times g \\ f _{g}  = 65kg \times 9.81 \frac{m}{s {}^{2} }  = 637.65
the unit of your fg will be in Newton [N]
so, first step solved, Fg is 637.65N
Fg is a field force by the way, and at the same time, the elevator is pushing up on him with 637.65N, so you draw another arrow pointing upwards, ending at the tip of the downwards arrow.
now let's calculate the force of the elevator
f = m \times a \\ f = 65 \times 5 \frac{m}{s {}^{2} }  \\ f = 325n
so you draw another arrow which is pointing downwards on him, because the elevator is accelating him upwards, making him heavier
the elevator force in this case is a contact force, because it only comes to existence while the two are touching, while Fg is the same everywhere
8 0
3 years ago
The net force experienced by an object is increased. What affect does this have on the acceleration of the object?
Evgesh-ka [11]

Answer:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Explanation:

hope it helps pls give me brainless

6 0
3 years ago
If the Moon had twice as much mass and still orbits Earth at the same distance, ocean bulges on Earth would be
Sophie [7]

Ocean bulges on Earth would be bigger if the Moon had twice as much mass and yet orbited the planet at the same distance. Option B is correct.

<h3>What is ocean bludge?</h3>

The fluid and moveable ocean water are drawn towards the moon by the gravitational attraction between the moon and the Earth.

The ocean nearest to the moon experiences a bulge as a result, and as the Earth rotates, the affected seas' locations shift.

The Moon's bulges in the oceans would be larger if it had twice the mass and orbited Earth at the same distance.

Hence option B is corect.

To learn more about the ocean bulge refer;

brainly.com/question/14373016

#SPJ1

6 0
1 year ago
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