13.5g H2O = 13.5/(2+16) = 0.75 mol H2O
Since for every O2 you can form 2 H2O, 0.75/2 = 0.375 mol of O2 will be needed to form 0.75 mol of H2O.
Converting from moles to molecules:
0.375 mol * 6.022 * 10^23 = 2.26 * 10 ^23 molecules
Answer:
C2H5OH(l)+3O2(g)⟶2CO2+3H2O(l)
Explanation:
Answer:
The answer to your question is False.
Explanation:
Data
1 mole of NH₄NO₃
0.75 moles of N₂O
Percent yield = 25%
Chemical reaction
NH₄NO₃ ⇒ N₂O + 2H₂O
Process
1.- Determine the theoretical yield
1 mol NH₄NO₃ ------------- 1 mol of N₂O
2.- Calculate the percent yield
Percent yield = Actual yield / Theoretical yield x 100
-Substitution
Percent yield = 0.75 / 1 x 100
-Simplification
Percent yield = 0.75 x 100
-Result
Percent yield = 75%
Conclusion
False, the actual percent yield is 75%
Answer:
i believe the answer to your question is parallax or parsecs. im sorry im not very specific in this!
Explanation:
The formula or chemical formula of a compound is same irrespective of source / mode of synthesis . Thus if a sample of compound has one carbon atom for every two atoms of oxygen (CO2), the formula will remains the same
So the answer is that for all other samples the compound X should hold this ration true.
