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cestrela7 [59]
3 years ago
15

Can anyone help me please?

Chemistry
1 answer:
Nady [450]3 years ago
5 0

10. Is A

11. Is D

12. Is D

13. Is B

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Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.110 atm to rise
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Answer:

t = 37.1 s

Explanation:

The equation for the reaction is given as;

                  2 N2O5(g)  --> 4 NO2 + O2

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change:        -2x                  +4x        +x

Final:          0.110 - 2x           +4x        +x

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x = 0.0133 atm

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0.110 - 2x

0.110 - 2 (0.0133) = 0.0834 atm

The integral rate law expression is given as;

ln ( [A] / [Ao] ) = -kt

k =  rate constant = 7.48*10^-3*s-1

ln (0.0834/0.11) = (7.48*10^-3)  t

upon solving, t = 37.1 s

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