Answer:
Ka = 1.78 × 10⁻⁵
Explanation:
Let's consider the following thermochemical equation.
CH₃COOH(aq) + H₂O(l) → CH₃COO⁻(aq) + H₃O⁺(aq) ∆G° = 27.1 kJ/mol
At 25°C (298 K), we can find the equilibrium constant (Ka) using the following expression.
∆G° = - R × T × lnKa
where,
R: ideal gas constant
T: absolute temperature
27.1 × 10³ J/mol = - (8.314 J/K.mol) × 298 K × lnKa
Ka = 1.78 × 10⁻⁵
Answer:
C4H6 + 2HBr = C4H8Br2
Explanation:
Alkynes are organic molecules made of the functional group carbon-carbon triple bonds and are written in the empirical formula of CnH2n−2. They are unsaturated hydrocarbons.
Furthermore, Halogenation reaction of any alkyne such as but-2-yne with any of the hydro halogenated compounds such as HBr, HCl, HF or HI will give an alkane that will have the same number of carbon atoms in the starting material and in the final product.
Halogenation reaction is a reaction that occurs when one or more halogens are added to a substance. Halogens is the seventh column in the periodic table and it include fluorine, chlorine, bromine, iodine, and astatine.
Karst topography can cause drinking water to become more polluted
Weight we calculate using W= force multiplied to displacement
Mass SI unit is Kg
Weight SI unit is Newton (N)
Mass
