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Sliva [168]
3 years ago
8

Write equations for the ionization of hno3 in water and the reaction of co32- with water. for each equation, identify the hydrog

en-ion donor and hydrogen-ion acceptor. then label the conjugate acid-base pairs in each equation.
Chemistry
1 answer:
alexira [117]3 years ago
8 0
Chemical reaction 1: HNO₃(aq) + H₂O(l) → NO₃⁻(aq) + H₃O⁺(aq).
Chemical reaction 2: CO₃²⁻(aq) + H₂O(l) → HCO₃⁻(aq) + OH⁻(aq).
According to  Bronsted-Lowry theory acid are donor of protons and bases are acceptors of protons (the hydrogen cation or H⁺<span>).
</span>In first reaction:
1) HNO₃(nitric acid) is hydrogen-ion donor and water is <span>hydrogen-ion acceptor.
2) HNO</span>₃ is acid and NO₃⁻ is conjugate base.
In second reaction:
1) water is hydrogen-ion donor and CO₃²⁻ hydrogen-ion acceptor.
2) CO₃²⁻ is base and HCO₃⁻ is conjugate acid.
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pH = 1.85

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The reaction of H₂NNH₂ with HNO₃ is::

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Moles of H₂NNH₂ and HNO₃ are:

H₂NNH₂: 0.0400L ₓ (0.200mol / L) = 8.00x10⁻³ moles of H₂NNH₂

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As moles of HNO₃ > moles of H₂NNH₂, all H₂NNH₂ will react producing H₂NNH₃⁺, but you will have an excess of HNO₃ (Strong acid).

Moles of HNO₃ in excess are:

0.01 mol - 8.00x10⁻³ moles = 2.00x10⁻³ moles of HNO₃ = moles of H⁺

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